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garik1379 [7]
4 years ago
11

A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: (5 points)

Mathematics
1 answer:
Aleksandr-060686 [28]4 years ago
7 0

Answer:

696.265 inches

Step-by-step explanation:

Radius = 27/2 = 13.5

2 semicircles + 2 lengths

(3.14 × 13.5²) + 2(62)

696.265 inches

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50 Points - Use the function f(x) to answer the questions:
faust18 [17]

f(x) = 2x^2 - x - 10

Part A:

x-intercepts: (-2,0), (5/2,0)

Part B:

The vertex is the minimum

vertex: (1/4, -81/8)

Part C:

A:

x: -2, -1, 1/4, 1, 2

y: 0, -7, -81/8, -9, -4

B:

3 0
3 years ago
A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
Alenkinab [10]

Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

5 0
3 years ago
What is the probability that a student failed the test GIVEN that they studied
puteri [66]

Answer:

1/12

Step-by-step explanation:

You are close but 1/27 includes people who did not study but still passed. If you want a singular value you should look at the value for the for only the people who studied even if they passed.

5 0
3 years ago
An auto mechanic converts a metric part to 0.492 in. The part comes only in fractional sizes given to the nearest 64th of an inc
tatuchka [14]

Answer:

the closest part the mechanic can chose is 0.5 inch

Step-by-step explanation:

fractional sizes given to the nearest 64th of an inch = 1/64 = 0.0156

the closest size to 0.492in = 0.492 + 0.0156 = 0.5076 inches

approximately, the closest part the mechanic can chose is 0.5 inch

4 0
3 years ago
Help please 10points
ikadub [295]

Answer:

Have you tried copying and pasting?

Step-by-step explanation:

ctrl c

ctrl v

6 0
3 years ago
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