Answer:
A) 5p = 60
Step-by-step explanation:
Since Chris and Paul both made putts totaling 60 and Chris made '4 times as many as Paul', setting up an equation with one variable makes the most sense:
p = number of putts for Paul
4p = number of putts for Chris
4p + p = 60
Combine like terms: 5p = 60
12t+10f+50. The t represents the $12 per student ticket. And the f represents the $10 per student for food
CD = BE so:-
5x + 1 = 6x - 2
-x = -3
x = 3
so CD = 5(3) + 1 = 16 answer
Answer:
16,000,000
Step-by-step explanation:
Answer:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:
And replacing we got:
So we are going to expect about 2,85 automobiles for this case.