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Fiesta28 [93]
3 years ago
12

3m+3n=36 8m+5n=31 Using the process of elimination

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

m=-29/3 and n=65/3

Step-by-step explanation:

The given system has equations:

3m+3n=36

8m+5n=31

Multiply the top equation by 5 and bottom equation by 3 to get:

15m+15n=180

24m+15n=93

Subtract the top equation from the bottom equation to get:

9m=-87

Divide both sides by 9

m =  -  \frac{29}{3}

We substitute this value into the first equation to get:

3( -  \frac{29}{3} ) + 3n = 36

3n = 36 + 29

3n = 65

n =  \frac{65}{3}

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From a group of 13 women and ​12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can
Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

                                                     ∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

        = 13!/5!.8!

        = 1287

12C₈ = 12!/(12₋8)! 8!

        = 12!/5! 8!

        = 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

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Math 2 Homework Mod 2.1 (Day 2) Absolute Value Functions
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The descriptions of the transformations are:

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  • Stretch factor: 2
  • Domain: set of all real numbers
  • Range: set of real numbers greater than or equal to 0

<h3>How to describe transformations, graph, and state domain & range using any notation?</h3>

The function is given as:

f(x) = -2|x + 6|

The above function is an absolute value function, and an absolute value function is represented as:

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Where

Vertex = (h, k)

Scale factor = a

So, we have:

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There is no restriction to the input values.

So, the domain is the set of all real numbers

The y value in (h, k) = (-6, 0) is 0

i.e.

y = 0

Because the factor is negative (-2), then the vertex is a minimum

So, the range is all set of real numbers greater than or equal to 0

Hence, the descriptions of the transformations are:

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