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3 years ago

The area of a rectangle is 25/42 and its width is 5/6. What is the length? ASAP

Mathematics

1 answer:

Serhud [2]3 years ago

8 0

Answer:

<h2> $length = \frac{25}{28}$ </h2>

Step-by-step explanation:

Let the length of the rectangle be l

Area of a rectangle = length × width

From the question

Area = 25/42

width = 5/6

Substitute the values into the above formula and solve for the length

That's

<h3> $length = \frac{area}{width}$ </h3>

So we have

<h3> $length = \frac{25}{42} \div \frac{4}{6} \\ = \frac{25}{42} \times \frac{6}{4} \\ = \frac{25}{7} \times \frac{1}{4}$ </h3>

We have the final answer as

Hope this helps you

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A movie theater has a seating capacity of 331. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults

nlexa [21]

Answer:

87 adults

174 children

70 students

Step-by-step explanation:

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1 year ago

The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.

serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that $p = 0.16$

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136
$

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

$E = \frac{n}{p}$

In this question, $n = 1, p = 0.16$ . So

$E = \frac{1}{0.16} = 6.25$

The expected number of at-bats until the next home run is 6.25.

6 0

2 years ago

Somebody please help me with my geometry.

eduard

Answer:

In order to read the degrees of an angle with a protractor, you must first determine if the angle is acute or obtuse. If it is acute, you use the measurement of the smaller number on the protractor. If it is obtuse, you use the larger measurement on the protractor.

For example, the measurement of the angle in question 1 seems to be about 74 degrees.

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2 years ago

Selena is driving to visit her grandmother who lives 325 miles away from Selena home. she travels an average of 60 miles per hou

GalinKa [24]

Answer:

Step-by-step explanation:

independent quantity=60 m/h

dependent =time taken=t

60 t=325

t=325/60=65/12=5 5/12 hours

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