Question

geqslant 0" alt=" {18e}^{ - 3x} \geqslant 0" align="absmiddle" class="latex-formula">
PLZ help​

Answer 1

Greetings from Brasil...

Note the graph of the function eˣ (or e⁻ˣ). We conclude that for any value of X, the result will be between 0 and +∞.\

So there is no value for X that the result of m.eˣ (or m.e⁻ˣ) is negative.

So you can answer:

For the equation of the statement of the question, with any value of X, we will always obtain a number greater than zero

S = {X | X∈ ℝ}

(OBS: we'll never get zero. We can get very close, but never zero)