Answer:
The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-interceptStep-by-step explanation:
Answer:
The distance between points P(x
1
,y
1
,z
1
) and Q(x
2
,y
2
,z
2
) is given by
PQ=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
+(z
2
−z
1
)
2
(i) Distance between points (2,3,5) and (4,3,1)
=
(4−2)
2
+(3−3)
2
+(1−5)
2
=
(2)
2
+(0)
2
+(−4)
2
=
4+16
=
20
= 2
5
(ii) Distance between points (−3,7,2) and (2,4,−1)
=
(2+3)
2
+(4−7)
2
+(−1−2)
2
=
(5)
2
+(−3)
2
+(−3)
2
=
25+9+9
=
43
(iii) Distance between points (−1,3,−4) and (1,−3,4)
=
(1+1)
2
+(−3−3)
2
+(4+4)
2
=
(2)
2
+(−6)
2
+(8)
2
=
4+36+64
=
104
=2
26
(iv) Distance between points (2,−1,3) and (−2,1,3)
=
(−2−2)
2
+(1+1)
2
+(3−3)
2
=
(−4)
2
+(2)
2
+(0)
2
=
16+4
=
20
= 2
5
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Part A:
The differential equation is:
y '= 0.08y
The initial condition is:
P (0) = 500 Part B:
The formula for this case is:
P (t) = 500exp (0.08 * t) Part C:
After five days we have to evaluate t = 5 in the equation.
We have then:
P (5) = 500 * exp (0.08 * 5)
P (5) = 745.9123488
Rounding:
P (5) = 746
Answer:
29
Step-by-step explanation:
There is a triangle embedded in triangle MNO, which is triangle PQO, and these are similar triangles in that their corresponding sides are always in the same ratio, which in this case is 2:1, as MP = MO due to the midpoint definition, and therefore MO is twice as long as MP. Same for NO and QO.
Now that we know the ratio, we can set 6x-4 = 2(-5x+64)
6x-4 = -10x +108
16x = 112
x = 7
Plug x back in for PQ, -5(7)+64 = 29
I'm pretty sure its B) 8 × 10^0
