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andre [41]
4 years ago
14

Help me pls only 10points

Mathematics
1 answer:
NeX [460]4 years ago
3 0

y=-7x+8

y=-7x-8

-7x+8=-7x-8

8=-8

x∈∅

B. No solutions

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An article bought for rs.800 is sold for 5/4 of the cost price. Find the profit percentage​
irina [24]

Answer:

the answer is 25% :D

3 0
3 years ago
Can someone answer this for me?
erik [133]

Answer:

sin = opposite / hypotenuse

cos = adjacent/hypotenuse

sin U = 4/5

cos U = 3/5

sin T = 3/5

cos T= 4/5

3 0
3 years ago
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A rectangle board is 1.2 meters long and 0.8 meters wide. What is the area of the board in millimeters
ivanzaharov [21]

Answer:

1200*800 = 960,000 mm²

Step-by-step explanation:

1 meter is 1000 mm and 0.8 meter is 800 mm

A=lw

5 0
3 years ago
You purchase 26 parking hours that you can use the next month to park your food truck at the fair. Weekday hours park $2 per hou
ICE Princess25 [194]

Answer:

Number of week day hours purchased  is 5

Step-by-step explanation:

Total number of Parking hours purchased = 26 parking hours

Parking cost on weekdays = $2 per hour

Parking costs on weekends = $10 per hour

Total amount spent on parking =  $220.

To Find:

Number of week days purchased = ?

Solution:

Let  

The number of week days purchased be x

The number of weekends purchased be  y

We know that the total hours purchased is 26

So,

x+y = 26

y = 26-x------------------------------------------------------(1)

Now the total cost is 220

(Total number of weekdays X cost per weekday ) +(Total number of weekends + cost per weekend) =220

Substituting the values

=>x\times 2 + y \times 10 = 220

=>x \times 2 + (26-x) \times 10 =220

=>2x + 260 -10x =220

=>260 -8x = 220

=>260 -220 =8x

=>40 = 8x

=>x=\frac{40}{8}

x= 5-------------------------------------------(2)

Now substituting (2) in (1) we get

y= 26-5

y= 21

7 0
4 years ago
Find the area of the region bounded by the line y=3x-6 and line y=-2x+8.
Vikentia [17]

Answer:

A = 12/5 units

Step-by-step explanation:

USING ALGEBRA:

We can find the intersection point between these two lines;

y = 3x - 6

y = -2x + 8

Set these two equations equal to each other.

3x - 6 = -2x + 8

Add 2x to both sides of the equation.

5x - 6 = 8

Add 6 to both sides of the equation.

5x = 14

Divide both sides of the equation by 5.

x = 14/5  

Find the y-value where these points intersect by plugging this x-value back into either equation.

y = 3(14/5) - 6

Multiply and simplify.

y = 42/5 - 6

Multiply 6 by (5/5) to get common denominators.

y = 42/5 - 30/5  

Subtract and simplify.

y = 12/5

These two lines intersect at the point 12/5. This is the height of the triangle formed by these two lines and the x-axis.

Now let's find the roots of these equations (where they touch the x-axis) so we can determine the base of the triangle.

Set both equations equal to 0.

(I) 0 = 3x - 6  

Add 6 both sides of the equation.

6 = 3x

Divide both sides of the equation by 3.

x = 2  

Set the second equation equal to 0.

(II) 0 = -2x + 8

Add 2x to both sides of the equation.

2x = 8

Divide both sides of the equation by 2.

x = 4

The base of the triangle is from (2,0) to (4,0), making it a length of 2 units.

The height of the triangle is 12/5 units.

Formula for the Area of a Triangle:

A = 1/2bh

Substitute 2 for b and 14/5 for h.

A = (1/2) · (2) · (12/5)

Multiply and simplify.

A = 12/5

The area of the region bounded by the lines y = 3x - 6 and y = -2x + 8 between the x-axis is 12/5 units.

3 0
3 years ago
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