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Deffense [45]
3 years ago
7

PLEASE HELPPPP!!!!!!!!!!!!

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0
Given:

Two endpoints of a diameter of a circle:

P (-7, -10)
Q (3, 2)

a) To find the center of the circle, find the midpoint of the two points:

midpoint:

(x2 - x1 )/ 2 , (y2 - y1) / 2

x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5

Therefore, the center of the circle is at C(4.5, 6.5)


 b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.

d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2 
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Answer:

62.8cubic units

Step-by-step explanation:

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4 0
2 years ago
Please help me on this question. 20 points guaranteed!!
julsineya [31]

Answer:

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Step-by-step explanation:

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2 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

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3 years ago
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2 years ago
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Pavlova-9 [17]

x= 34 /3  thats what I got 34/3=11.333333


7 0
3 years ago
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