Step-by-step explanation:
The position of the mouse at time t is 4 + 12t.
The position of the cat at time t is 17t.
When the positions are equal:
4 + 12t = 17t
4 = 5t
t = 0.8
It takes 0.8 seconds.
Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
525,600 minutes in a year
3,330,000 * 525,600 = answer
Type it into a calculator and you'll have your answer
The correct answer is A)<span>.02m(n - 5) - .02(m + 10)</span>
<span>F= 9/5 C + 32
or
</span><span>F= 9/5(C+32)
</span> Hoped this helped:)