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evablogger [386]
2 years ago
14

10 Using the quadratic formula to solve x2 = 5 – X, what are the values of x?

Mathematics
1 answer:
loris [4]2 years ago
6 0

x^2 = 5 - x

x^2 + x - 5 = 0

-1 +/-\frac{ \sqrt{ {1}^{2} - 4(1 \times  - 5) } }{2}

x = (1 + √21) / 2

x = (1 - √21) / 2

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Explain: How would you solve the equation? Place the steps below in the correct order.
nirvana33 [79]

use the distributive property

combine alike terms

add the negative number to the other side

combine alike terms

then divide on both sides to get the variable by itself

8 0
3 years ago
A regular hexagon has an apothem of 14.7 inches and a perimeter of 101.8 inches. What is the area of the hexagon?
Neporo4naja [7]

<u>Answer</u>

748.23 in²


<u>Explanation</u>

Apothem a line from the centre of a regular polygon at right angles to any of its sides. This can be said to be the height of the triangle in a polygon.

The base of the  hexagon = 101.8 ÷ 6

                                            = 19.96666..

                                            = 19.9667 inches

Area of the  hexagon = 1/2 × height × base length × 6

                                     = 1/2 × 14.7 × 19.9667 × 6

                                      = 748.23 in²

7 0
3 years ago
Read 2 more answers
Help if you can -
yulyashka [42]

Answer:

1.875 commercials a minute

Step-by-step explanation:

4 0
2 years ago
Un sastre vende dos camisas a S/. 60 cada una. En la primera camisa gana 25% de lo que costo hacerla y en la otra pierde 25% de
weeeeeb [17]

Me no speak espanol i thivcyieuqo

Step-by-step explanation:

5 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
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