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pantera1 [17]
2 years ago
15

80% is what fraction

Mathematics
1 answer:
Mariana [72]2 years ago
6 0
80% as a fraction is 4/5
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What is the equation in point-slope form of the line that passes through the point (−1, −3) and has a slope of 4?
Nimfa-mama [501]

The equation of line in point-slope form of the line that passes through the point (−1, −3) and has a slope of 4 is:

y+3=4(x+1)

Step-by-step explanation:

Given

m=4

and

Point = (x1,y1) = (-1,-3)

The general form of point-slope equation of line is:

y-y_1=m(x-x_1)\\Putting the values of m, x_1 and y_1\\y-(-3)=4(x-(-1))\\y+3=4(x+1)

Hence,

The equation of line in point-slope form of the line that passes through the point (−1, −3) and has a slope of 4 is:

y+3=4(x+1)

Keywords: Point-slope form, Slope

Learn more about equation of line at:

  • brainly.com/question/4361464
  • brainly.com/question/4390083

#LearnwithBrainly

5 0
3 years ago
16.437 rounded to the nearest tenths is
Akimi4 [234]

Answer:

16

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
2 years ago
If a half gallon milk costs $1.24, what is the cost per pint?
PIT_PIT [208]

Hello! The answer is: $0.31


7 0
2 years ago
Suppose that g(x) = f(x + 8) + 4. Which statement best compares the graph of g(x) with the graph of f(x)?
UNO [17]
The graph of g(x) is the same as that of f(x), EXCEPT that the graph of f(x) has been translated 8 units to the left and 4 units up.
4 0
3 years ago
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