2 years ago

Solve the equation. 12a=11

1 answer:

5 0

A= 11/12 i hope this helped !!!

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Basile [38]

The way your question is worded, the probability is zero. One ace is not two aces.

5 0

3 years ago

Vadim26 [7]

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

$P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}$

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

4 0

3 years ago

Art [367]

6.75 miles per half hour !!!!!!!

7 0

3 years ago

Snowcat [4.5K]

Y+7
Y is the variable and 7 is the constant.

7 0

3 years ago

nikitadnepr [17]

Substitute 3x+1 for x. Then solve from there

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3 years ago