Solve the equation. 12a=11

WILL MARK BRAINLIEST!!!NEED HELP ASAP!! Carrie will spin the arrow on the spinner four times. What is the probability that the a

sladkih [1.3K]

The probability that the arrow will land on any of them once is 1/4.

The probability that the arrow will land on any of them twice is 1/4 * 1/4. This is because the probability of Event A and Event B is P(B) * P(A).

Based on this:

$P(a\cap b\cap c\cap d) = \frac{1}{4}\times \frac{1}{4}\times\frac{1}{4}\times\frac{1}{4}\\\\=\frac{1}{4\times4\times4\times 4}\\=\frac{1}{256}$

1/256

Hope this helps, let me know if I missed anything!

5 0

2 years ago

Read 2 more answers

Two straight lines have equations y = p x + 4 y = p x + 4 and p y = q x − 7 p y = q x − 7 , where p p and q q are constants. The

kolbaska11 [484]

Answer:

q = $\frac{8}{3}$

Step-by-step explanation:

The point of intersection (3, 1 ) is the solution to both equations

Using

y = qx - 7 and substituting x = 3, y = 1

1 = 3q - 7 ( add 7 to both sides )

8 = 3q ( divide both sides by 3 )

$\frac{8}{3}$ = q

6 0

2 years ago

Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio

morpeh [17]

Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

$H(x,y) = (8,6)$

San Antonio

$T(x,y) = (-6,-7)$

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

$S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)]$ (1)

$S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]$

$S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)$

$S(x,y) = (4.5,2.75)$

Andra

$A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)]$ (2)

$A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]$

$A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)$

$A(x,y) =(1, -0.5)$

Emily

$E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)]$ (3)

$E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]$

$E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)$

$E(x,y) = (-2.5, -3.75)$

a. If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver?

Emily's beginning point is the Andra's stop point, that is, $A(x,y) =(1, -0.5)$ .

Emily should begin her turn as the third driver at point (1, -0.5).

b. At what point does Emily's turn to drive end?

Emily's turn to drive end at point (-2.5, -3.75).

7 0

2 years ago

Brainliest if it is right

Elena-2011 [213]

Answer:

there are three ( 3 ) possible outcomes that are 1,2 and 3

7 0

1 year ago

Read 2 more answers

What are the possible numbers of positive, negative, and complex zeros of f(x)=x^6-x^5-x^4+4x^3-12x^2+12?

Vadim26 [7]

$f(x)=x^6-x^5-x^4+4x^3-12x^2+12\\\\12:\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}}$

8 0

2 years ago