Answer:
they were in two places in flint and Birmingham and in Birmingham it is hot but flint of cold the Simi is they both have Sunday school for Joetta
Explanation:
use in your own words teachers know when your not trust me.
Answer:
B
Explanation:
From Newton's law of motion, we have:
V^2 = U^2 + 2gH
Where V and U are final and initial velocity respectively.
H is the height.
For the object to have a sustain a maximum height it means the final velocity of the object is zero.
By computing the height of the object sustain by A, we have:
0^2 = 2^2 -2×10×H
0= 4 -20H
4 = 20H;
H= 0.2m
For object B we have;
0^2 = 1^2 -2×10×H
0 = 1 -20H
H = 1/20= 0.05m
From computing the height sustain by both objects, we see object B is projected at a shorter height into atmosphere than A.
Hence object B will return to the ground first.
Answer with Explanation:
We are given that
Dipole moment=
C-m
Because ![1 e=1.6\times 10^{-19} C](https://tex.z-dn.net/?f=1%20e%3D1.6%5Ctimes%2010%5E%7B-19%7D%20C)
![1 nm=10^{-9} m](https://tex.z-dn.net/?f=1%20nm%3D10%5E%7B-9%7D%20m)
![a^x\cdot a^y=a^{x+y}](https://tex.z-dn.net/?f=a%5Ex%5Ccdot%20a%5Ey%3Da%5E%7Bx%2By%7D)
Magnitude of electric field,E=
N/C
a.We have to find the magnitude of torque on the dipole when
dipole is parallel to the electric field
i.e![\theta=0](https://tex.z-dn.net/?f=%5Ctheta%3D0)
We know that
![\tau=PEsin\theta](https://tex.z-dn.net/?f=%5Ctau%3DPEsin%5Ctheta)
Substitute the values then we get
![\tau=0.8\times 10^{-28}\times 8\times 10^{4} sin0=0](https://tex.z-dn.net/?f=%5Ctau%3D0.8%5Ctimes%2010%5E%7B-28%7D%5Ctimes%208%5Ctimes%2010%5E%7B4%7D%20sin0%3D0)
Because sin 0=0
![\tau=0](https://tex.z-dn.net/?f=%5Ctau%3D0)
b.![\theta=90^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D90%5E%7B%5Ccirc%7D)
![\tau=0.8\times 10^{-28}\times 8\times 10^4sin90](https://tex.z-dn.net/?f=%5Ctau%3D0.8%5Ctimes%2010%5E%7B-28%7D%5Ctimes%208%5Ctimes%2010%5E4sin90)
By using ![sin90^{\circ}=1](https://tex.z-dn.net/?f=sin90%5E%7B%5Ccirc%7D%3D1)
![\tau=6.4\times 10^{-28+4}=6.4\times 10^{-24}Nm](https://tex.z-dn.net/?f=%5Ctau%3D6.4%5Ctimes%2010%5E%7B-28%2B4%7D%3D6.4%5Ctimes%2010%5E%7B-24%7DNm)
Nm
c.![\theta=30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5E%7B%5Ccirc%7D)
![\tau=0.8\times 10^{-28}\times 8\times 10^4sin 30](https://tex.z-dn.net/?f=%5Ctau%3D0.8%5Ctimes%2010%5E%7B-28%7D%5Ctimes%208%5Ctimes%2010%5E4sin%2030)
Nm
By using ![sin30^{\circ}=\frac{1}{2}](https://tex.z-dn.net/?f=%20sin30%5E%7B%5Ccirc%7D%3D%5Cfrac%7B1%7D%7B2%7D)
![tau=3.2\times 10^{-24} Nm](https://tex.z-dn.net/?f=tau%3D3.2%5Ctimes%2010%5E%7B-24%7D%20Nm)
d.Potential energy, U=![-PEcos\theta](https://tex.z-dn.net/?f=-PEcos%5Ctheta)
![\theta=0](https://tex.z-dn.net/?f=%5Ctheta%3D0)
![U=-0.8\times 10^{-28}\times 8\times 10^4cos 0=-6.4\times 10^{-28}J](https://tex.z-dn.net/?f=U%3D-0.8%5Ctimes%2010%5E%7B-28%7D%5Ctimes%208%5Ctimes%2010%5E4cos%200%3D-6.4%5Ctimes%2010%5E%7B-28%7DJ)
Because cos 0degree=1
Answer:
The mechanical advantage of a machine is 2. Mechanical advantage MA is the ratio of output (generated by the machine) force to input (applied to the machine) force. So MA = 2 means that for example if you apply 100 N then your machine will multiply that force and generate 200 N .