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Mnenie [13.5K]
3 years ago
8

Suppose that you drop a marble from the top of a building, which is about 830m tall. If you ignore air resistance, how long will

it take for the marble to hit the ground?
Physics
1 answer:
Harman [31]3 years ago
3 0

Answer:

so, if you drop the marble and there is no air resistance it could take around 10-15 sec

Explanation:

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A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hittin
LUCKY_DIMON [66]

Answer:

-47.04

Explanation:

Divide 12 m by 2.5 m/s which equals 4.8s

And then use 4.8s to multiply it with -9.8

4.8(-9.8)= -47.04 m/s

Hope this helped!! :)

8 0
3 years ago
Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
anastassius [24]

The guys before me was almost right. But instead of it being vertical it is horizontal.

8 0
3 years ago
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You are interested in space travel and want to learn more facts about space travel. Which would be the best source of informatio
Tpy6a [65]
A book or a professor
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3 years ago
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A small plastic ball with a mass of 7.10 x 10⁻³ kg and with a charge of +0.161 µC is suspended from an insulating thread and han
GuDViN [60]

Answer:

3.16097\times 10^{-8}\ C

Explanation:

T = Tension on the string

E = Electric field

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

As the forces balance themselves we have the equations

Tcos30=mg

Tsin30=Eq

Dividing the equations we get

tan30=\dfrac{Eq}{mg}\\\Rightarrow E=\dfrac{mgtan30}{q}\\\Rightarrow E=\dfrac{7.1\times 10^{-3}\times 9.81tan30}{0.161\times 10^{-6}}\\\Rightarrow E=249770.33291\ N/C

Electric field is given by

E=\dfrac{Q}{A\epsilon}\\\Rightarrow Q=EA\epsilon\\\Rightarrow Q=249770.33291\times 0.0143\times 8.85\times 10^{-12}\\\Rightarrow Q=3.16097\times 10^{-8}\ C

The magnitude of the charge on each plate is 3.16097\times 10^{-8}\ C

6 0
3 years ago
the radius of a ball is increasing at a rate of 2 mm per second. how fast is the volume of the ball increasing when the diameter
otez555 [7]

Step 1: Define an equation that relates the volume of a sphere to its radius.

V = 4/3*π*r3

Step 2: Take the derivative of each side with respect to time (we will define time as "t").

(d/dt)V = (d/dt)(4/3*π*r3)

dV/dt = 4πr2*dr/dt

Step 3: We are told in the problem statement that diameter is 100m, so therefore r = 50mm. We are also told the radius of the sphere is increasing at a rate of 2mm/s, so therefore dr/dt = 2mm/s. We are looking for how fast the volume of the sphere is increasing, or dV/dt.

dV/dt = 4π(50mm)2*(2mm/s)

dV/dt = 62,832 mm3/s

7 0
2 years ago
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