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3 years ago

8

Suppose that you drop a marble from the top of a building, which is about 830m tall. If you ignore air resistance, how long will

it take for the marble to hit the ground?

1 answer:

Harman [31]3 years ago

3 0

Answer:

so, if you drop the marble and there is no air resistance it could take around 10-15 sec

Explanation:

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Acceleration due to gravity on earth is:

Olenka [21]

C because gravity is holding everything down

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3 years ago

The ____ is a line drawn at a right angle to a barrier. a. normal c. node b. ray d. wave front

Natalija [7]

Answer:

a. normal

Explanation:

In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.

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Calculate the pressure exerted by mercury column of 76cm high at its bottom. Given that the density of mercury is 13600kg/m³ and

raketka [301]

Answer:

P = 101292.8

Explanation:

Use

Pressure p = H D g

H = height ( in metric)

D = density ( in metric )

g = gravity

So

H = 76 cm = 0.76 m

D = 13600 kg/m3

And g = 9.8

P = HDg

= 0.76× 13600×9.8

= 101292.8 pascal

Or = 1.012928 × 10^5

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3 years ago

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Which is the most likely location in the home for mold growth? A) bathroom windows B) living room furniture C) computer keyboard

FinnZ [79.3K]

Answer:

A

Explanation:

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3 years ago

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In a certain clock, a pendulum of length L1 has a period T1 = 0.95s. The length of the pendulum

gulaghasi [49]

Answer:

Ratio of length will be $\frac{L_2}{L_1}=1.108$

Explanation:

We have given time period of the pendulum when length is $L_1$ is $T_1=0.95sec$

And when length is $L_2$ time period $T_2=1sec$

We know that time period is given by

$T=2\pi \sqrt{\frac{L}{g}}$

So $0.95=2\pi \sqrt{\frac{L_1}{g}}$ ----eqn 1

And $1=2\pi \sqrt{\frac{L_2}{g}}$ -------eqn 2

Dividing eqn 2 by eqn 1

$\frac{1}{0.95}=\sqrt{\frac{L_2}{L_1}}$

Squaring both side

$\frac{L_2}{L_1}=1.108$

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4 years ago