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Zigmanuir [339]
4 years ago
10

What is greater 19/34, 19/36

Mathematics
2 answers:
goldenfox [79]4 years ago
6 0
The answer is 19/34
Wewaii [24]4 years ago
4 0

Answer:19/34

Step-by-step explanation:

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Margaret has a monthly clothes budget of 50 she maps the Amy of money she spends each month to the number of items of clothing s
Scorpion4ik [409]

It is said that the graph plotted is the money spent to the number of items of clothing bought.

It will look like this:

The domain by definition is the set of inputs.

The constraint on the domain here is the monthly spending cannot be greater than $50.

So the domain will be [0,50] in dollars on the x-axis.

4 0
1 year ago
Michael has less than $20 to spend for a taxi. The charge for the taxi is
stiks02 [169]

Answer:

2m + 6 < 20

Step-by-step explanation:

A flat $6 plus $2 per mile is represented as 2m + 6, with m as the number of miles you can go.

This 2m + 6 must be LESS THAN Michael's $20. Therefore, this gives us:

<em><u>2m + 6 < 20</u></em>

2m: $2 per mile

6: the initial cost

20: how much money Michael has

7 0
3 years ago
R = {(-3, -2), (-3, 0), (-1, 2), (1, 2)} Select all numbers that are in the range.
Vera_Pavlovna [14]
Keep in mind that the domain is always the x-coordinates and the range the y-coordinates,

\bf R = \{(-3, \stackrel{\downarrow }{-2}), (-3, \stackrel{\downarrow }{0}), (-1, \stackrel{\downarrow }{2}), (1, \stackrel{\downarrow }{2})\}\impliedby \stackrel{\downarrow }{range}
6 0
3 years ago
Read 2 more answers
If point (4,5) is in the graph of a function, which equation must be true?
Serjik [45]
If (4,5) is a point on the graph of a function, then if x=4, f(x)=5. so f(4)=5.
4 0
4 years ago
Read 2 more answers
(06.04 MC) Find the area of the following shape.
svetlana [45]

Check the picture below.

well, the purple trapezoid, has a height of 5, and its bases are of 5 units and 8 units, recall the bases are the parallel sides in a trapezoid.

now, the yellow rectangle, is a 6x5, and it has those two green triangles in it, well, if we simply get the area of the rectangle, 30 anyway, and subtract the areas of those green triangles, what's leftover, is the rest of the shape on points DEFA.

keeping in mind that the green triangles have a base of 4 and a height of 3 for the one atop and base of 5 and height of 2 for the bottom one.

\bf \stackrel{\textit{purple trapezoid}}{\cfrac{\stackrel{h}{5}(\stackrel{a}{5}+\stackrel{b}{8})}{2}}~~+~~\left[ \stackrel{\textit{yellow square}}{(6\cdot 5)}-\stackrel{\textit{two green triangles}}{\cfrac{1}{2}(4)(3)-\cfrac{1}{2}(5)(2)} \right] \\\\\\ \cfrac{5(13)}{2}+[30-6-5]\implies \cfrac{65}{2}+[19]\implies \cfrac{103}{2}\implies 51\frac{1}{2}

7 0
4 years ago
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