Answer:
![\mu = 8.8\\\sigma = 1.9](https://tex.z-dn.net/?f=%5Cmu%20%3D%208.8%5C%5C%5Csigma%20%3D%201.9)
Now we are supposed to find probabilities that the response time is between 5 and 10 minutes i.e P(5<x<10)
Formula : ![z= \frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
at x = 5
![z= \frac{5-8.8}{1.9}](https://tex.z-dn.net/?f=z%3D%20%5Cfrac%7B5-8.8%7D%7B1.9%7D)
![z=-2](https://tex.z-dn.net/?f=z%3D-2)
at x = 10
![z= \frac{10-8.8}{1.9}](https://tex.z-dn.net/?f=z%3D%20%5Cfrac%7B10-8.8%7D%7B1.9%7D)
![z=0.6315](https://tex.z-dn.net/?f=z%3D0.6315)
P(-2<z<0.6315)=P(z<0.6315)-P(z<-2)
Refer the z table
P(-2<z<10)=0.7357-0.0228=0.7129
So, the probability that response time is between 5 and 10 minutes is 0.7129
b)the response time is less than 5 minutes
at x = 5
![z= \frac{5-8.8}{1.9}](https://tex.z-dn.net/?f=z%3D%20%5Cfrac%7B5-8.8%7D%7B1.9%7D)
![z=-2](https://tex.z-dn.net/?f=z%3D-2)
P(x<5)=P(z<-2)=0.0228
So, the probability that the response time is less than 5 minutes is 0.0228
c)the response time is more than 10 minutes
at x = 10
![z= \frac{10-8.8}{1.9}](https://tex.z-dn.net/?f=z%3D%20%5Cfrac%7B10-8.8%7D%7B1.9%7D)
![z=0.6315](https://tex.z-dn.net/?f=z%3D0.6315)
P(x>10) = 1-P(x<10) = 1-P(z<0.63) = 1-0.7357 = 0.2643
So, The probability that the response time is more than 10 minutes is 0.2643
108 is the answer to your question
A standard number cube has 6 sides....
probability of rolling a 5 is 1/6......probability of not rolling a 5 is 5/6
Hello :
hello : <span>
1 ) if : x</span>ـــــــ> ± ∞
<span>
limf(x) = b ....(b</span>∈R) so : y=b is the equation of
the line horizontal asymptote.
<span>
2) if : x</span>ـــــــ>
a ...(a∈R)<span>
limf(x) = ± ∞
<span>so : x=a is the equation of the
line vertical asymptote.</span></span>
<span><span>hint : in this exercice : a = 2 or a = 7 but : b=2</span></span>