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torisob [31]
3 years ago
8

[Geometry] Is ABC DEF? If so, name the postulate that applies.

Mathematics
2 answers:
Temka [501]3 years ago
5 0

Answer: C. Might not be congruent.

Step-by-step explanation:

In the given figure, we have two right triangles ΔABC and ΔDEF.

Also, it is given that,

\angle{A}=\angle{D}\\\angle{B}=\angle{E}\\\angle{C}=\angle{F}

So by, AAA similarity rule we can say  ΔABC and ΔDEF are similar.

But we cannot say it is congruent.

We need at-least one side equal in both triangles to prove it congruent.

For example :-All the equilateral triangles are similar but not congruent as the side lengths vary as per triangle but the angles remain same  60^{\circ}.

IRISSAK [1]3 years ago
3 0
C. because u can't name a congruent triangle by angle angle angle
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What is 23/2 converted into a mixed numeral
Cerrena [4.2K]

Answer:

11 1/2

Step-by-step explanation:

22 divided by 2 is 11, and there is 1 left over. So that is 1/2. The mixed number is 11 1/2

4 0
3 years ago
Review the following information about vectors q and r.
Vitek1552 [10]
<h3>Answer:  a = -1  (fourth choice)</h3>

==========================================

Work Shown:

q = (-4, 1) is one vector

r = (a,3) is another vector

The resultant vector is

q+r = (-4,1)+(a,3)

q+r = (-4+a,1+3)

q+r = (-4+a,4)

Multiply both sides by 7

7(q+r) = 7*(-4+a,4)

7(q+r) = (7*(-4+a),7*4)

7(q+r) = (-28+7a, 28)

---------------

Since 7(q+r) = (-35, 28), we know that,

(-28+7a, 28) =  (-35, 28)

which leads to

-28 + 7a = -35

when we equate the x components of each vector. Let's solve for 'a'

-28 + 7a = -35

7a = -35+28

7a = -7

a = -7/7

a = -1

--------------

Check:

q = (-4,1)

r = (a,3) = (-1,3)

q+r = (-4,1)+(-1,3)

q+r = (-4+(-1), 1+3)

q+r = (-5, 4)

7*(q+r) = 7*(-5, 4)

7*(q+r) = (7*(-5), 7*4)

7*(q+r) = (-35, 28)

The answer is confirmed.

7 0
2 years ago
Read 2 more answers
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Answer:

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6 0
2 years ago
Read 2 more answers
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Answer:

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7 0
3 years ago
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Answer:

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8 0
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