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pav-90 [236]
3 years ago
6

Mr. Rogers recorded the height of 15 students from two of his classes. Based on these samples, what generalization can be made?

The median student height in Class A is equal to the median student height in Class B. The range of the student heights in Class A is greater than the range of the student heights in Class B. The mean student height in Class A is less than the mean student height in Class B. The median student height in Class A is more than the median student height in Class B.
Mathematics
1 answer:
Sati [7]3 years ago
6 0
You are not giving enough information but in one of the calsses the average of student's height might be greater than the other class beacause one of the two classes needs to have 1 extra person than the other calss
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S KM ∥ JN? Why or why not?
bixtya [17]

Given: We have the given figure through which we can see

LK=16,

KJ=10,

LM=24,

MN=15

To Find: Whether KM || JN and the reasoning behind it.

Solution: Yes, KM || JN because \frac{16}{10}= \frac{24}{15}

Explanation:

For this solution, we use the concept of Similar Triangles.

Now, KM || JN if ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).

Now, ∠MLK=∠NLJ

To prove similarity of the two triangles, we have to show that the sides are proportional. In other words, LK:KJ = LM:LN

LK:KJ=LM:LN\\\\ \frac{LK}{KJ} =\frac{LM}{LN}\\\\\frac{16}{26}= \frac{24}{39}\\\\

which is true as both sides simplify to \frac{8}{13}

Thus, we see that ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).

Therefore, KM || JN.

To come to the reasoning, notice that

\frac{LK}{LJ} =\frac{LM}{LN}\\\\\frac{LK}{LK+KJ} =\frac{LM}{LM+MN}\\\\\frac{LK+KJ}{LK} =\frac{LM+MN}{LM}\\\\1+\frac{KJ}{LK}=1+ \frac{MN}{LM}\\\\\frac{LK}{KJ} =\frac{LM}{MN}

In other words, \frac{16}{10}= \frac{24}{15}


4 0
3 years ago
Read 2 more answers
I
iren2701 [21]

Answer:

The distance between points A and B is 13

Step-by-step explanation:

We need to find distance between points A and B

Looking at the graph,

Point A : (2,6) and Point B: (-3,-6)

We need to find the distance between these points.

The formula used is: Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

We have Points A : (2,6) and  B: (-3,-6)

So, x_1=2, y_1=6, x_2=-3, y_2=-6

Putting values in formula and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Distance=\sqrt{(-3-2)^2+(-6-6)^2} \\Distance=\sqrt{(-5)^2+(-12)^2} \\Distance=\sqrt{25+144} \\Distance =\sqrt{169}\\Distance = 13

So, the distance between points A and B is 13

6 0
3 years ago
The table is shows the fraction of the votes that each candidate received. If 230 students voted, how many students voted for ea
barxatty [35]

3/5 * 230 = 138 votes for Nyemi

3/10 * 230 = 69 votes for Luke

1/10 * 230 = 23 votes for Natalie

***************** DOUBLE-CHECK ****************

138 + 69 + 23 = 230  Correct!!


6 0
3 years ago
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The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restric
lana66690 [7]
What type of math is this problem? Is it advanced?

6 0
3 years ago
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Triangle ABC is shown below.<br> What is the length of line segment AC?
Rzqust [24]

Answer:

The length of the line segment AC is equal to 14

Step-by-step explanation:

The triangle above is an isosceles triangle, In an Isosceles triangle the two angles; B and C are the same, hence the two sides; AB and AC are also the same.

AB=2x    and AC= 3x - 7

AB = AC

which implies;

2x = 3x - 7

subtract 3x from both-side of the equation

2x - 3x = 3x -3x -7

-x = -7

Multiply through by -1

x = 7

But we were ask to find the the length of the line segment AC

AC = 3x - 7

substituting x = 7 into the above equation will yield;

AC = 3(7) - 7 = 21 - 7 =14

Therefore the length of the line segment AC is equal to 14

3 0
3 years ago
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