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3 years ago

5a + 18 < −27 pre algibra

Mathematics

2 answers:

Grace [21]3 years ago

5 0

Answer:

X < -9

Step-by-step explanation:

5a +18 < -27

5a < -27 -18

5a < - 45

5a/5 < - 45/5

a < - 9

Answred by Gauthmath

Mrac [35]3 years ago

3 0

Answer: -9

Step-by-step explanation:

5a+18 < -27

5a< -27-18

5a<-45

a< -45/5

a< -9

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How many times larger is 8*10^6 than 2*10^2

bogdanovich [222]

The first step for solving this question is put both of your given expressions into one and then subtract them. This will look like the following:
8 × $10^{6}$ - 2 × 10²]
Now to make the calculation easier,, factor the expression.
(8 × $10^{4}$ - 2) × 10²
Evaluate the power inside the parenthesis.
(8 × 10000 - 2) × 10²
Evaluate the power outside the parenthesis.
(8 × 10000 - 2) × 100
Multiply the numbers inside the parenthesis.
(80000 - 2) × 100
Subtract the numbers in the parenthesis.
79998 × 100
Lastly,, multiply the numbers together to get your final answer.
7999800
This means that 8 × $10^{6}$ is 7999800 times larger than 2 × 10².
Let me know if you have any further questions.
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8 0

3 years ago

Change this into decimal step by step plz

nika2105 [10]

Answer:

2.6

Step-by-step explanation:

3/5 ---> ?/100

100/5 ---> 20

3 20 60

-- x = -------

5 20 100

60/100 = 6/10

6/10 as a decimal is 0.6

2 + 0.6

= 2.6

<h2>Hope this helps!!</h2>

7 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

4 years ago

How do you convert fractions to decimals and percents

Levart [38]

Well when you convert fractions to decimals, you simply divide the numerator by the dominator.
To convert decimals to percents, you take the fraction and divide the numerator by the dominator and times that by 100.
For example, 4/25*100=16%

4 0

4 years ago

-2x + 3x - 5 = 6 - 21<br><br> FIND x

trasher [3.6K]

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

5 0

3 years ago