Answer:
-11, -10, -9
Step-by-step explanation:
The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.
_____
I like to work "consecutive integer" problems using the average value of the integers involved. The average of <u>two</u> consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are <u>three</u> consecutive integers, so their average is the middle one.
If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...
(x -1) +(x) + (x+1) = 3x = -30
x = -30/3 = -10 . . . . . the same average we computed above.
x -1 = -11 . . . . . the smaller of the other two integers
x +1 = -9 . . . . . the larger of the other two integers
6*3
9*2
18*1
Cant you look this stuff up?
well, here's how you can do this:
take any value y, then divide by 2.5 to get x
so, you can get (these are just a couple of pairs, they are an infinite number of pairs for any equation like this!):
if y=0
x=0
if y=2.5
x=1
if y=5
x=2
graph:
Answer: -7, 12
Step-by-step explanation:
a+b = 5
a*b = -84
a = 5-b
(5-b)*b = -84
-b^2 + 5b + 84 = 0
(-b - 7)(b + 12) = 0
The roots are -7 and 12.
I'm not sure what â€" stands for