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tamaranim1 [39]
3 years ago
12

A minor league baseball team plays 104 games in a season. If the team won 16 more than 3 times as many games as they lost, how m

any wins and losses did the team have?
Mathematics
1 answer:
erica [24]3 years ago
7 0

Games lost = x

Games won = 16 + 3x

Total games = 104

104 = (x) + (16 + 3x)

104 = 4x + 16

4x = 88

x = 22

Games lost = 22

Games won = 82

Hope this helps!! :)

You might be interested in
A government bureau publishes annual price figures for new mobile homes. A simple random sample of 36 new mobile homes yielded t
Oliga [24]

Answer:

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

<em>49, 56.4, 72.6, 60.1, 65, 64.8, 56.5, 52, 53.2,  </em>

<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

8 0
3 years ago
Will someone please check my answer , im not quite sure about it ?
Oksi-84 [34.3K]
Yes you are right.

Keep up the good work:)
6 0
3 years ago
Right in terms of I -72
mixer [17]
What’s your question
4 0
3 years ago
Which of these points lies on the line described by the equation below y-4=-2(x-6)?​
Burka [1]

Answer: x=4

Step-by-step explanation:

3 0
3 years ago
3a+8b-5c<br> 6a- 9b+4c<br> -7a+b+2c<br>how do I solve this by solving using addition operation
jeyben [28]

Answer: 2a+c


Step-by-step explanation: You add all variables that are positive then you subtract by negatives or vice versa. Add 3a+6a-7a yes subtract the 7a which gets you 2a. Add 8b+b-9b, you get 9b-9b which is 0 so you don’t need b in the problem anymore. -5a+4c+2c then you get c, because it is 1 c. So your answer is 2a+c. :P Hope this helped.


3 0
3 years ago
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