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sladkih [1.3K]
3 years ago
11

If a leopard can run 500 years in 1/2min how many yards could they run in 1 hour​

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

?

Step-by-step explanation: how do expect us to know this

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Identify the independent variable and dependent variable in the situation:
kramer
I think the independent variable is the number of people and the dependent is the wait time. I see it as the wait time DEPENDS on how many people are in line. This one is kinda confusing tho
3 0
3 years ago
Which expression equals 6x − 5y + 2 − 8x + 3( y + 5)? A) 3x − 2y + 17 B) −3x + 2y + 17 C) −2x − 2y + 17 D) −2x − 2y − 17
inysia [295]

Answer:

<u>C) −2x − 2y + 17</u>

Step-by-step explanation (PEMDAS):

First, we do <u>3 (y + 5)</u> because of the parenthesis:

6x − 5y + 2 − 8x + 3y + 15

Since there are no exponents, multiplication ,or division, we will add and subtract. But we have to make sure we <u>combine like terms</u>. X with X's, Y with Y's and constants with constants. And ALWAYS go from left to right

6x − 5y + 2 − 8x + 3y + 15

<u>−2x</u> − 5y + 2 + 3y + 15

−2x <u>− 2y</u> + 2 + 15

<em>−2x − 2y</em><em> </em><em>+ </em><em><u>17</u></em><em>.</em>

8 0
3 years ago
Find perimeter of the figure thanks and round to the nearest hundredth
Gnom [1K]

Answer:

40.56

Step-by-step explanation:

you need the circumference of the cirle aka perimeter of circle so  8(pi) and then because its only half, divided by 2... 12.56

now you hgave circumference so add 12.56 to 28 and there you go. you can round how ever necessary

7 0
3 years ago
Read 2 more answers
Calculate the volume of the cube
Andrews [41]

Answer:

s to the power of 3

Step-by-step explanation:

6 0
3 years ago
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Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
2 years ago
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