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Umnica [9.8K]
3 years ago
14

The door on the computer center has a lock which has five buttons numbered from 1 to 5. The combination of numbers that opens th

e lock is a sequence of five numbers and is reset every week.
(a) How many combinations are possible if every button must be used once?
(b) Assume that the lock can also have combinations that require you to push two buttons simultaneously and then the other three one at a time. How many more combinations does this permit?
Mathematics
1 answer:
gladu [14]3 years ago
7 0

Answer:

a) 121 combinations

b) 124 combinations

Step-by-step explanation:

a) 5 possible number without repeating any will give us =

5 possible numbers* 4 possible numbers* 3 possible numbers* 2possible numbers + 1 possible numbers = 121 combination

b) 5 possible number but repeating 1 will give us 5 possible numbers* 4 possible numbers * 3 possible numbers* 2possible numbers

+4 possible number

124 combination

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bija089 [108]

Answer:

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SIZIF [17.4K]
Hey!


The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x

<em>New Equation {Changed by Distribution} :</em>
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The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

<em>Old Equation :</em>
5x - 50 = 30 - 15x

<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
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<em>Old Equation :</em>
5x = 80 - 15x

<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
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Now we divide both sides by 20 to get x on it's own.

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<em>New Equation {Changed by Dividing Both Sides by 20} :</em>
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Finally, all we have to do is solve to find x.

<em>Old Equation :</em>
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x = 4

<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,  x = 4.

Hope this helps!


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