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dangina [55]
2 years ago
9

Endpoint: (-9,-1), midpoint: (8,14) given the midpoint and one endpoint of a line segment, find the other endpoint.

Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

Answer:

 (25, 29)

Step-by-step explanation:

The midpoint formula can be solved to give an expression for one end point of a line segment in terms of the other end point and the midpoint.

<h3>Formula</h3>

The midpoint (M) of segment AB is found from ...

  M = (A +B)/2

Solving for B, we get ...

  B = 2M -A

<h3>Application</h3>

For A(-9, -1) and M(8, 14), we find the end point B to be ...

  B = 2(8, 14) -(-9, -1)

  B = (16 -(-9), 28 -(-1)) = (25, 29)

The other end point is (25, 29.

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Step-by-step explanation:

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In point B:

2 waggons so more tyres would be required if they ordered any more waggons.  

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Subtract the following using horizontal method<br> i.)2x from-5x<br> ii.)-5a from 18a
Lena [83]

Answer:

\huge{ \boxed{ \text{ i. \:  \ - 7x}}}

\huge{ \boxed{ \text{ii. \:  23a}}}

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

☄ Question : Subtract the following using horizontal method :

  • i. 2x from -5x
  • -5a from -18a

✎ Step - by - step Explanation :

  • 2x from -5x

In horizontal method , terms are arranged in same row and put sign for subtraction and remove the brackets and then simplify.

\longrightarrow{ \sf{ - 5x - (2x)}}

\longrightarrow{ \sf{ - 5x - 2x}}

Like terms can be added or subtracted. Only coefficients of like terms can be added or subtracted.

\longrightarrow{  \boxed{\sf{ - 7x}}}

Likewise , Let's do next too:

  • -5a from 18 a

\dashrightarrow{ \sf{  18a - ( - 5a)}}

Remember : \sf{( - ) \times (  - ) = (  + )}

\dashrightarrow{ \sf{ 18a + 5a}}

\dashrightarrow{ \boxed{ \sf{ 23a}}}

And we're done!

Hope I helped!

Have a wonderful time ツ

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