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3 years ago

13

How do you use a scientific calculator?

1 answer:

egoroff_w [7]3 years ago

8 0

Try to start by reading the manual it came with. If it didn't come with a manual, then your teacher in school will teach you how to use it for specific commands. Otherwise it's just like using a regular calculator but with the ability to do more things, what do you need to know on it?

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Factor X^3-7x^2-5x+35 by grouping. What is the resulting expression

WARRIOR [948]

Answer:

(x-7) (x^2-5)

Step-by-step explanation:

x^3-7x^2-5x+35

Factor out an x^2 from the first two terms and -5 from the last 2 terms

x^2 (x-7) -5(x-7)

Factor out (x-7)

(x-7) (x^2-5)

5 0

3 years ago

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Find X.<br><br> A) 3<br><br> B) 4<br><br> C) 5<br><br> D)6

lbvjy [14]

I think it's 3 or 4.

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3 years ago

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Combining like terms with negative coefficients & distribution

Leno4ka [110]

$- 4(z + 3) - 4(5 - 4z) \\ = - 4z - 12 - 20 + 16z \\ = 12z - 32$

6 0

3 years ago

Find the 78th term of the arithmetic sequence<br> -12,-13,-14,

creativ13 [48]

Answer:

-89

Step-by-step explanation:

The first term of the sequence is a1 = -12.

The common difference between terms is ...

d = -13 -(-12) = -1

The generic term is given by ...

an = a1 +d(n -1)

Then the 78th term is ...

a78 = -12 +(-1)(78 -1) = -12 -77

a78 = -89

8 0

2 years ago

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

2 years ago

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