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larisa86 [58]
3 years ago
3

If the function y = xa − 31 is a linear function, what is the value of a?

Mathematics
1 answer:
goblinko [34]3 years ago
6 0
If we are to assume that a is an exponent on the x, then a would have to be 1, because x^1 is the same thing as just plain old x.  If we put an exponent other than a 1 on that x, it is no longer linear.  If we put an exponent of 2, the function would be a quadratic.  If we put an exponent of 3, the function would be a cubic.  If we put an exponent of 4, the function would be a quartic.  Linear is just a plain line in the form y = mx + b.
You might be interested in
Integrate x<br><img src="https://tex.z-dn.net/?f=x4" id="TexFormula1" title="x4" alt="x4" align="absmiddle" class="latex-formula
Dmitrij [34]

Answer:

The result of the integration is \frac{x^5}{5}

Step-by-step explanation:

Integration of a power of x:

The integration of a power of x is:

\int x^{n} dx = \frac{x^{n+1}}{n+1}

In this question:

n = 4. So

\int x^{4} dx = \frac{x^{4+1}}{4+1} = \frac{x^5}{5}

The result of the integration is \frac{x^5}{5}

4 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=77°, and CD = 41 feet. Find the length of BC to the nearest foot.
OLga [1]

Answer:

182 ft

Step-by-step explanation:

When you are not given a diagram, always draw one for yourself (see diagram).

When you have a right triangle (triangle with 90° angle), you can use the trigonometry ratios, You can remember them using SohCahToa. It is read like this:

<u>s</u>inθ = <u>o</u>pposite/<u>h</u>ypotenuse           Soh

<u>c</u>osθ = <u>a</u>djacent/<u>h</u>ypotenuse          Cah

<u>t</u>anθ = <u>o</u>pposite/<u>a</u>djacent                Toa

"θ" means the angle of reference (the angle you are talking about).

We are looking for the length of BC, which is the <u>hypotenuse</u>. I labelled it "d" (lowercase D) because it is opposite to ∠D.

We know ∠C = 77°. This will be our angle of reference (replace θ).

The side we know is DC, also known as "b" (lowercase B) because it's opposite to ∠B. "b" is the <u>adjacent</u> side when θ = C because "b" is touching ∠C.

Take the general trig. formula that has <u>hypotenuse</u> and <u>adjacent</u>: (cosine ratio)

cosθ = adjacent/hypotenuse

Substitute the variables specific for this problem.

cosC = b/d

Substitute the values you know.

cos77° = (41 ft) / d

Isolate "d" to the left side

dcos77° = d*\frac{41ft}{d}     Multiply both sides by "d"

dcos77° = 41 ft                          

dcos77° / cos77° = 41 ft / cos77°        Divide both sides by cos77°

d = 41 ft / cos77°                      Input into calculator

d = 182.261874....... ft           Unrounded answer

d ≈ 182 ft                       Rounded to nearest foot (whole number)

Remember d = BC. It's often easier to use one letter for calculations.

Therefore the length of BC is about 182 feet.

8 0
3 years ago
If EG = 59, and EF = 8x - 14, while FG = 4x + 1
lyudmila [28]

Answer:

x = 6

Step-by-step explanation:

EG = 59

EF = 8x - 14

FG = 4x + 1

to find the value of x

EF + FG = EG (same line)

8x - 14 + 4x + 1 = 59

12x -13 = 59

12x = 59 + 13

12x = 72

x = 72 ÷ 12

x = 6

You can even cross check for correct answer

EF + FG = EG

instead of x place the x's value we got

8x - 14 + 4x + 1 = 59

8 (6) - 14 + 4 (6) + 1 = 59

48 - 14 + 24 + 1 = 59

34 + 25 = 59

59 = 59

CROSS - CHECKED

4 0
3 years ago
Please help me!!!!!!!
Helen [10]
First we will find the value of x.

To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.

We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.

angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24

Now we can use 24 for x and find the value of angle QRO

angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67

So the answer choice B is the right answer.

Hope this helps :)<span />
6 0
4 years ago
Please someone answer this please
gladu [14]

Option C:

\frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

To find which expression is equivalent to the given expression.

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

Using exponent rule: \frac{1}{a^m}=a^{-m}, \ \  \frac{1}{a^{-m}}=a^{m}

    $=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }

    $=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }

Using exponent rule: {a^m}\cdot{a^n}=a^{m+n}

    $=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }

   $=\frac{-18 a^{2} b^{11}}{-12 }

Divide both numerator and denominator by the common factor –6.

   $=\frac{3 a^{2} b^{11}}{2 }

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }

Therefore, \frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Hence Option C is the correct answer.

8 0
4 years ago
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