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boyakko [2]
3 years ago
10

If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at rando

m (assume the child may write the same letter twice), what is the probability that they are both vowels?
Mathematics
1 answer:
Savatey [412]3 years ago
7 0
The formula for probability is # of favorable outcomes divided by the total number of outcomes. 

So we know that there are a total of 5 letters. The child writes two letters, so we will have x/5 * x/5. Now, it is asking, what is the probability that they are both vowels.

We can see that a, i, and e are vowels, so the probability if the child were to write one letter would be 3/5. Since he is writing 2, you can multiply 3/5 * 3/5, which would give you your answer, 9/25. Therefore the probability that both letters are vowels is 9/25.

Hope this helps! Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps! :D


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At a particular restaurant, each chicken wing has 75 calories and each slider has 250 calories. A combination meal with chicken
VikaD [51]

Know a are:

CW=75. SL= 250. Y= 2x

CW= X= number of wings

SL= Y= number of sliders

X+Y= Total number of items, which can be rewritten as X+2X= total

Plug in the calories for the total

2(75X) +250X= 800

150x+250X= 400X= 800

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0.0035289

Step-by-step explanation:

From the question;

mean annual salary = $63,500

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