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Marina CMI [18]

2 years ago

7

The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Cels

ius. Based on the equation, which of the following must be true?
A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of
5
9
degree Celsius.
A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
A temperature increase of
5
9
degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.
A) I only
B) II only
C) III only
D) I and II only

1 answer:

FromTheMoon [43]2 years ago

4 0

Isjxbcj is on 3 2020 today

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Cost to store: $140<br><br> Markup: 25%

anastassius [24]

The actual cost to the store = $140
Percentage of markup = 25%
Amount of markup in cost = (25/100) * 140 dollars
= 35 dollars
Then
Sell price in the store = (35 + 140) dollars
= 175 dollars
So the sell price of the product at the store after addition of the markup price will be $175.

7 0

3 years ago

Question 1: Find the equation of the line through point (5,4) and perpendicular to y=−43x−2. Use a forward slash (i.e. "/") for

Mariulka [41]

Answer:

Question 1: y = 3/4x + 1/4.

Question 2: y = 6/5x + 7/5.

Step-by-step explanation:

Question 1: A line perpendicular to another line would have a slope that is the negative reciprocal of the other line. If the slope of the first line is -4/3, the slope of a line perpendicular to the first would have a slope of 3/4.

Since the line goes through (5, 4), we can just put the points into the equation, y = 3/4x + b.

4 = 3/4(5) + b

b + 15/4 = 4

b = 16/4 - 15/4

b = 1/4

So, the equation of the line is y = 3/4x + 1/4.

Question 2: 5x + 6y = -6

6y = -5x - 6

y = -5/6x - 1

As stated before, a line perpendicular to another will have a slope that is the negative reciprocal of the other. So, the slope of the other line is 6/5.

The line goes through (-2, -1), so we can put the points into the equation, y = 6/5x + b.

-1 = 6/5(-2) + b

b - 12/5 = -5/5

b = -5/5 + 12/5

b = 7/5

So, the equation of the line is y = 6/5x + 7/5.

Hope this helps!

8 0

3 years ago

1. Jemima wants to make chocolate chip walnut brownles. Chocolate chips come in a 12oz bag that costs $3. Walnuts

fomenos

Answer:

4 bags of chocolate chips and 1 bag of walnuts.

Step-by-step explanation:

Find how many ounces are in 3 pounds:

16 oz = 1 lb

16 oz × 3 = 3 lbs

48 oz = 3 lbs

Variable x = number of chocolate chips

Variable y = number of walnuts

4x + 1y = 15

Keep in mind it must equal up to 48 oz and be $15 or under.

4 bags × 12 oz = 48 oz

1 bag × 4 oz = 4 oz

48 oz + 4 oz = 52 oz > 48 oz

4 bags × $3 = $12

1 bag × $2 = $2

$12 + $2 = $14 < $15

Both requirements have been met.

7 0

2 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

Image is down below :)

zhuklara [117]

-3, 1 is the answer because the spot is on the -3 and in the first low with the Y-axis and stuff .

4 0

3 years ago

Read 2 more answers