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3 years ago

6

An item originally costs $10. It's on sale for 50% off with and additional 20% off. If the sales tax is 10.1%, what is the final

cost of this item? (I will mark brainliest if you help)

1 answer:

Sergio039 [100]3 years ago

4 0

Answer:

Final Cost = $4.01

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Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean

Maksim231197 [3]

The correct option is: a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is: $z= \frac{X-\mu}{\sigma}$

Newborn males have weights with a mean $(\mu)$ of 3272.8 g and a standard deviation $(\sigma)$ of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69$

According to the normal distribution table, $P(z=-2.69)=0.0036 = 0.36\%$

Now, newborn females have weights with a mean $(\mu)$ of 3037.1 g and a standard deviation $(\sigma)$ of 706.3 g.

So, the z-score for the newborn female who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18$

According to the normal distribution table, $P(z=-2.18)=0.0146 = 1.46\%$

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>, so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0

3 years ago

Factor by grouping<img src="https://tex.z-dn.net/?f=%284y%5E3%20%2B%2028y%5E2%29%20%2B%20%28y%20%2B%207%29" id="TexFormula1" tit

Inessa05 [86]

We have the following expression given:

$(4y^3+28y^2)+(y+7)$

We can start selecting as common factor 4y^2 and we got:

$4y^2(y+7)+(y+7)$

Now we can select y+7 as common factor and we got:

$(y+7)\left\lbrack 4y^2+1\right\rbrack$

So then our final answer would be:

$(y+7)(4y^2+1)$

3 0

1 year ago

a family buys a car for $20,000. the value of the car decreases about 20% each year. after 6 years, the family decides to sell t

Neporo4naja [7]

No, the car is losing value not gaining it.

7 0

3 years ago

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6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

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2 years ago

Aimee must add together the following numbers:3.50 + 4.00 + (−1.25) + (−7.50) + 5.25 + 2.00As her first step, Aimee writes:(3.50

vladimir2022 [97]

The answer is 'C' <em>Aimee used the Associative and Commutative Properties to put numbers that are easy to add next to each other. </em>

<em> </em> I hope you have a nice day!

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3 years ago

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