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Ket [755]
3 years ago
9

Solve 49x + 9= 49x+84 how many solution it has

Mathematics
1 answer:
MArishka [77]3 years ago
3 0
I think it has one answer of 75
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One third of a number t is equal to 7
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7 / 1/3
therefore
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Simplify. What is your answer 8x + 9d + 3x -5d
BlackZzzverrR [31]

Answer:

11x + 4d

Step-by-step explanation:

8x + 9d + 3x -5d

To simplify this we have to group them by their like terms i.e.

= 8x + 3x + 9d - 5d

= 11x + 4d

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3 years ago
Find the missing length of the triangle.<br> 26 in.<br> a<br> 24 in.
Elis [28]

Answer:

10

Step-by-step explanation:

26^2-24^2=100

sqrt of 100 is 10

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I don’t know the answer I’m not that smart help<br><br>Thank you
Stolb23 [73]

Answer:

H

Step-by-step explanation:

The tiny squares equal to 12 already so it is already greater therefore x=0

6 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
2 years ago
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