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IrinaVladis [17]
3 years ago
11

The school cafeteria serves tacos every 6th day and cheeseburgers every 8th day. If tacos and cheeseburgers are on today's menu,

how many days will it be until they are both on the menu at the same time again?
Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0
They will never be on the same day again .
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Pls helppppppppppppppppppppp
Julli [10]

Answer:

10 2/3

Step-by-step explanation:

Multiply 4 and 2 and then multiply 2 and 4. If you do that then you get 8 8/3. You then just take the numerator and turn it into whole numbers to get 10 2/3.

4 0
3 years ago
Find the product ( x ≠ ? )
dsp73

Answer:

-3

Step-by-step explanation:

if x= -3

the denominator becomes 0 and the fraction becomes undefined.

8 0
3 years ago
What is the inequalities of 4(-4x-3)>36
adelina 88 [10]

Answer:

x<-3

Step-by-step explanation:

-16x-12>36

-16x>48

x<-3

4 0
2 years ago
3 x 5 = 15 5 x 3 = 15 shows the ________ property? Commutative
Ulleksa [173]

Answer:

commutative property of multiplication

Step-by-step explanation:

The commutative property of multiplication is correct. The commutative property of multiplication is basically arranging the numbers in any way and it won't change the product.

The associative property of multiplication is arranging the numbers in parenthesis and it won't change the product either.

7 0
2 years ago
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
2 years ago
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