Answer:
idk how to do this
Step-by-step explanation:
Answer:
See proof below
Step-by-step explanation:
Assume that V is a vector space over the field F (take F=R,C if you prefer).
Let 
. Then, we can write x as a linear combination of elements of s1, that is, there exist 
and 
such that 
. Now, 
then for all 
we have that 
. In particular, taking 
with 
we have that 
. Then, x is a linear combination of vectors in S2, therefore 
. We conclude that 
.
If, additionally 
then reversing the roles of S1 and S2 in the previous proof, 
. Then 
, therefore 
.
1. -6
2. 4
2. -1
The positive numbers will out rule the negative number. It's sort of like placing blocks over another set of blocks. :)
Answer:
1.6
Step-by-step explanation:
the number 6 is one place after the decimal so it's where the tenth is, and the number after is 4 or below which in this case is 2 so the number rounds down to 1.6
Answer:
∠DAB = ∠DBA
Then AD=DB from above statement
