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Nezavi [6.7K]
3 years ago
11

Matt buys a new fish tank. The fish tank is in the shape of a cuboid. The diagram shows water in the tank. 30 cm 30 cm 100 cm Ma

tt knows 1000 cm' = 1 litre 1 gallons = 4.5 litres He can keep 2 small fish in the tank for every 1 gallon of water in the tank. Matt thinks he can keep more than 36 small fish in the tank. Is Matt correct?​
Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer: Yes, but only if he houses 37, 38, 39, or 40 fish

Anything larger than 40 and he'll need more room.

==========================================================

Explanation:

The tank is 30 cm by 30 cm by 100 cm. The volume is 30*30*100 = 90,000 cm^3 which is shorthand for "cubic centimeters".

We're told that 1000 cm^3 = 1 liter, which means the 90,000 cm^3 converts to (90,000)/(1000) = 90 liters.

The fish tank is 90 liters.

Since 1 gallon = 4.5 liters, this means the 90 liter tank converts to 90/(4.5) = 20 gallons

----------------------------

Your teacher mentions "He can keep 2 small fish for every 1 gallon".

Since the tank is 20 gallons, that means he can keep 20*2 = 40 fish. This value is larger than 36, so Matt is correct to a point. If Matt is thinking 37, 38, 39, or 40 fish then he would be correct. If Matt is wanting more than 40 fish, then he'll need a bigger tank.

In short, he can't have any number over 36 and can only have 4 specific values (the four values mentioned earlier).

So technically, Matt is correct, but strong clarification is needed.

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The given line segment has a midpoint at (−1, −2).
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Answer:

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505/19

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How to solve y=350(1+0.75)t
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Newberg City Cafe recently introduced a new flavor of coffee. They served 23 grande cups and 51 jumbo cups of the new coffee tod
yuradex [85]

Answer:

Grand coffee cup = 1469 gm

Jumbo coffee cup = 60 gm

Step-by-step explanation:

Let x be the grande coffee cup and y be the jumbo coffee cup.

Solution:

From the first statement. They served 23 grande cups and 51 jumbo cups of the new coffee today, which equal a total of 36,846 grams.

So, the equation is.

23x+51y = 36846 ---------(1)

From the second statement. They served 58 grande cups and 68 jumbo cups of the new coffee tomorrow, which equal a total of 59460 grams.

58x+68y=59460 ----------(2)

Solve the equation 1 for x.

23x = 36846-51y

x=\frac{36846}{23}-\frac{51}{23}y

x=1602-\frac{51}{23}y ---------(3)

Substitute x=1602-\frac{51}{23}y in equation 2.

58(1602-\frac{51}{23}y)+68y=59460

92916-\frac{51\times 58}{23}y+68y=59460

-\frac{2958}{23}y+68y=59460-92916

\frac{-2958+1564}{23}y=-33456  

\frac{-1394}{23}y=-33456

Using cross multiplication.

y=\frac{-23\times 33456}{-1394}

y = 55.99

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Substitute y = 60 in equation 3.

x=1602-\frac{51}{23}\times 60

x=1602-\frac{3060}{23}

x=1602-133.04

x = 1469 grams

Therefore, grand coffee cup = 1469 gm and jumbo coffee cup = 60 gm

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3 years ago
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