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Kruka [31]
4 years ago
15

Please help right away thankkkksssss

Mathematics
1 answer:
Arisa [49]4 years ago
8 0

Hi,

Irrational means not a whole number so b,c, and d are irrational. but to be more safe i would go for d.


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It took team tool bella 2 1/3 hours to hike 4 2/3 miles. whats their average speed in mph
aleksandrvk [35]
Divide # miles by # of hours to find average mph.

=4 2/3 ÷ 2 1/3
change to improper fractions
= 14/3 ÷ 7/3
multiply by reciprocal/inverses of 7/3
= 14/3 * 3/7
= (14*3)/(3*7)
= 42/21
= 2

Hope this helps! :)
3 0
3 years ago
The square shown below has a perimeter of 6x-20 units. What is the value of x?
Vaselesa [24]
Basically divide it by four.

2.5x-5 I'm pretty sure. Let me know if I'm wrong.
5 0
3 years ago
The boundary lines for the system of inequalities is given in the graph.
diamong [38]

Answer:

C)

region C

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

\displaystyle y ≤ -x + 2

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

\displaystyle y ≥ 2x - 3

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]

So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.

I am joyous to assist you anytime.

4 0
4 years ago
Read 2 more answers
Lines l and m are parallel. When they are cut by the two transversals below, a triangle is formed.
marshall27 [118]

Answer:

<2 = 34degrees

Step-by-step explanation:

Find the diagram attached below:

First we need to get <1;

<1 + 74 = 180 (angle on a straight line)

<1 = 180 - 74

<1 = 106degrees

Also, <1 + <2 + 40 = 180 (sum of angle in a triangle)

106+<2 + 40 = 180

146 + <2 = 180

<2 = 180-146

<2 = 34degrees

3 0
3 years ago
A. Find y in terms of x if
givi [52]

Answer:

A.y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

B.Therefore the solution is defined on the interval:

6≤ x ≤ +∞

Step-by-step explanation:

Given differential equation is

\frac{dy}{dx} = x^4y^{-1}

\Rightarrow \frac{dy}{dx} =\frac{ x^4}{y}

\Rightarrow y dy = x^4dx

Integrating both sides:

\Rightarrow\int y dy = \int x^4dx

\Rightarrow \frac{y^2}{2} =\frac{x^5}{5} +C........(1)

Given y(0)= 6

it means y=0 when x=6

Putting x=6 and y=0 in the equation (1)

\therefore \frac{0^2}{2} =\frac{6^5}{5} +C

\Rightarrow C=-\frac{6^5}{5}

Equation (1) become:

\Rightarrow \frac{y^2}{2} =(\frac{x^5}{5} -\frac{6^5}{5})

\Rightarrow y} =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

Therefore y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

(B)

The quantity under root must greater than or equal to zero.

Therefore,

2(\frac{x^5}{5} -\frac{6^5}{5})} \geq0

\Rightarrow \frac{x^5}{5} -\frac{6^5}{5}} \geq0

\Rightarrow \frac{x^5}{5} \geq\frac{6^5}{5}}

\Rightarrow x^5\geq {6^5

\Rightarrow \sqrt[5]{x^5} \geq \sqrt[5]{6^5}

\Rightarrow x\geq {6

When x≥0 then the value of 2(\frac{x^5}{5} -\frac{6^5}{5})} is real other wise the value of 2(\frac{x^5}{5} -\frac{6^5}{5})} is imaginary.

Therefore the solution is defined on the interval:

6≤ x ≤ +∞

8 0
4 years ago
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