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ladessa [460]
3 years ago
6

I need the answer so please help it is worth 88 points

Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

24

Step-by-step explanation:

If she did all 3of them today then you subtract a day from each one then it would look like this

5+4+15=24

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1.The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fai
ZanzabumX [31]

Answer:

568 ADULTS

284 CHILDREN

Step-by-step explanation:

5C+10A=7100

A=2C

5C +10(2C)=7100

5C+20C=7100

25C=7100

C=284

A=2C

A=568

BRAINLIEST???

8 0
2 years ago
HURRY I GIVE BRAINLIEST AND EXTRA POINTS !!!!
Temka [501]
11/3 is equal to 3 2/3
8 0
3 years ago
A radio station ordered hats and coffee mugs to give away as prizes. A total of 1,000 of these items were ordered, and 3 times a
marshall27 [118]

Answer:

The options are not shown, so i will answer in a general way.

Let's define the variables:

h = number of hats

m = number of mugs.

We know that a total of 1000 items were ordered, then:

h + m = 1000

We also know that we have 3 times more mugs than hats, this can be written as:

m = 3*h

Now we have the system of equations:

h + m = 1000

m = 3*h

To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:

h + m = 1000

h + (3*h) = 1000

Now we can solve this equation for h, and find the number of hats ordered.

4*h = 1000

h = 1000/4 = 250

There were 250 hats ordered.

3 0
2 years ago
P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the
nirvana33 [79]
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span>                                      =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x 
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2)   (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
 
Then y = 10 - 2(4) = 2.
 So the point, P, is (4,2).
8 0
3 years ago
What is the sum of 3 sixteen and 2 nines
Mama L [17]


16+16+16+9+9=32+16+9+9=48+9+9=57+9=66

The answer is 66

5 0
3 years ago
Read 2 more answers
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