I think it is 22.5, since molly has 75% of the packs
Answer:
Step-by-step explanation:
Assuming this integral:

We can do this as the first step:

Now we can solve the integral and we got:

![\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B12%7D%5CBig%7C_%7B-%5Cinfty%7D%5E0%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Be%5E%7B60%2A0%7D%20-e%5E%7B-%5Cinfty%7D%5D)
So then we see that the integral on this case converges amd the values is 1/12 on this case.
D is the answer bro
Hit the thank button
= 18 *

+

brackets first
= 18 * 16 + 36 next exponents
= 288 + 36 then multiplication
= 324 finally addition
Lisa was right, she used BEDMAS properly while Rob treated the

as (

-

). This made it 18 * 16 + (81 - 9) = 288 + 72 = 360.
Answer:
the first choice 2 ; -2 ; 6 :-6
Step-by-step explanation:
1) method : you can put this values 2 ; -2 ; 6 :-6 you are 0
2) method you can solve this equation
x^4-40x^2+144=0
let : x² = t and t ≥ 0
t² -40t +144 = 0
Δ = b²- 4ac a= 1 b = - 40 c = 144
Δ =(-40)²- 4(1)(144= 1600 -576 = 1024=32²
t1 = (40+32)/2 = 36 = 6²
t1 = (40-32)/2 = 4 = 2²
but : x² = t and t ≥ 0
1)case : x² = 6² x = 6 or x= -6
2() case : x² =2² x = 2 or x= -2