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a_sh-v [17]
3 years ago
8

A doctor takes an uber from the airport to a hotel. The uber driver charges an $2.50 initial charge plus $2.65 per mile? Which e

quation can be used to find y, the total cost of the trip, if x represents the number of miles of the trip?
F. y = 2.50x + 2.65
G. y = 2.65(x + 2.50)
H. y = 2.65x - 2.50
J. y = 2.65x + 2.50
Mathematics
1 answer:
RideAnS [48]3 years ago
6 0

Opinion Answer: G or J

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Dolly gave Molly 6/8 packs of sweets. Molly had 18 packs of sweets. How many packs of sweets did Dolly start out with?
LenaWriter [7]
I think it is 22.5, since molly has 75% of the packs
6 0
3 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value of each that converges.
____ [38]

Answer:

\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}  

Step-by-step explanation:

Assuming this integral:

\int_{-\infty}^0 5 e^{60x} dx

We can do this as the first step:

5 \int_{-\infty}^0 e^{60x} dx

Now we can solve the integral and we got:

5 \frac{e^{60x}}{60} \Big|_{-\infty}^0

\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]

\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}  

So then we see that the integral on this case converges amd the values is 1/12 on this case.

6 0
3 years ago
15. What's the correct letter name for Z1 below?
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D is the answer bro


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6 0
3 years ago
Rob and Lila try to simplify 18 x 4² + (9 - 3)². Rob simplifies the expression and gets 360. Lila simplifies it and gets 324. Wh
s344n2d4d5 [400]
= 18 * 4^{2} + 6^{2}          brackets first

= 18 * 16 + 36      next exponents

= 288 + 36           then multiplication

= 324                   finally addition

Lisa was right, she used BEDMAS properly while Rob treated the (9 - 3)^{2} as (9^{2} - 3^{2}). This made it 18 * 16 + (81 - 9) = 288 + 72 = 360.
5 0
3 years ago
Find the real zeros<br> x^4-40x^2+144=0
IRISSAK [1]

Answer:

the first choice 2 ; -2 ; 6 :-6

Step-by-step explanation:

1) method : you can put this values 2 ; -2 ; 6 :-6 you are 0

2) method  you can solve this equation

x^4-40x^2+144=0

let : x² = t   and t ≥ 0

t² -40t +144 = 0

Δ = b²- 4ac    a= 1           b = - 40         c = 144

Δ =(-40)²- 4(1)(144= 1600 -576 = 1024=32²

t1 = (40+32)/2 = 36 = 6²

t1 = (40-32)/2 = 4 = 2²

but :  x² = t   and t ≥ 0

1)case    :    x² = 6²       x = 6 or x= -6

2() case : x² =2²          x = 2 or x= -2

4 0
3 years ago
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