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Vinil7 [7]
3 years ago
8

Which blocks have a volume between 20 and 30 cubic centimeters?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer: c

Step-by-step explanation:

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\bf cot(\theta)=\cfrac{1}{tan(\theta)}
\qquad \qquad 
csc(\theta)=\cfrac{1}{sin(\theta)}\qquad \qquad sin(-\theta )=-sin(\theta )
\\\\\\
\textit{also recall }sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\
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\bf \cfrac{csc^2(x)-cot^2(x)}{sin(-x)cot(x)}\implies \cfrac{\frac{1}{sin^2(x)}-\frac{cos^2(x)}{sin^2(x)}}{-sin(x)\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{1-cos^2(x)}{sin^2(x)}}{-cos(x)}
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\cfrac{\frac{sin^2(x)}{sin^2(x)}}{-cos(x)}\implies \cfrac{1}{-cos(x)}\implies -sec(x)
7 0
3 years ago
Any chance anyone can help me if the last question I had post
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6 0
3 years ago
What is the greatest common factor of 32 and 56​
alina1380 [7]

Answer:

8

Step-by-step explanation:

List the factors of each number

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

Separate and find the GCF

Then the greatest common factor is 8.

Thanks for letting me help!!

4 0
3 years ago
Read 2 more answers
8000000000000000 minus 280000000000000 In standard form
zavuch27 [327]

Answer:

7.72 * 10^15

Step-by-step explanation:

8*10^15 - 2.8*10^14 = 7.72 * 10^15

5 0
3 years ago
A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an
lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of v_2=613.87m/sec

Step-by-step explanation:

We have given internal diameter of the garden hose d_1=0.740in=1.8796cm

So radius r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm

So area A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2

Water in the hose has a speed of 4 ft/sec

So v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)

Number of holes n = 36

Diameter of each hole d_2=0.1397cm

So radius r_2=0.0698cm

So area A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2

From continuity equation

A_1v_1=nA_2v_2

2.7733\times 121.92=36\times 0.0153\times v_2

v_2=613.87m/sec

7 0
3 years ago
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