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3 years ago

X^2+ 6x - 4 = 3x + 6

Mathematics

2 answers:

jolli1 [7]3 years ago

4 0

Answer:

x=2

x=-5

Step-by-step explanation:

You need to get everything on one side to have a quadratic equation:

x^2+6x-4 -(3x+6) = x^2+3x-10

All factors of 10 are 1*10 and 2*5.

5-2 = 3 and 5*-2 = -10

Factoring x^2+3x-10 gives us (x-2)(x+5)

x=2

x=-5

Tanzania [10]3 years ago

4 0

Answer:

x=-5 x=2

Step-by-step explanation:

x^2+ 6x - 4 = 3x + 6

Subtract 3x from each side

x^2+ 6x-3x - 4 = 3x-3x + 6

x^2+ 3x - 4 = 6

Subtract 6 from each side

x^2+ 3x - 4-6 = 6 - 6

x^2 +3x -10 =0

Factor

What 2 numbers multiply to -10 and add to 3

5*-2 =-10

5+-2 = 3

(x+5) (x-2) =0

Using the zero product property

x+5 =0 x-2 =0

x=-5 x=2

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Find A, given that a = 18.2, B=62°, and C= 48°. Round to the nearest whole degree.

fomenos

Answer:

Step-by-step explanation:

If we are given angles B and C, then all we have to do is add them together and then subtract that from 180 since all the angles of a triangle have to add up to equal 180.

62 + 48 = 110

180 - 110 = 70

Angle A = 70°

5 0

3 years ago

I have these factoring questions I need help with.

snow_lady [41]

$f(x)=4x^2+4x-3$

1. Determine y-intercept.

The y-intercept is (0,-3). Substitute x = 0 in the equation as we get f(x) = -3 as the y-intercept.

2. Determine the zeros.

Factor the polynomials first. $(2x-1)(2x+3)$ This is the factored form. The zeros are the roots of equation. Therefore, the zeros are 1/2 and -3/2

3. Determine the Axis of Symmetry

We can solve this by using the formula of $x=-\frac{b}{2a}$ However, I'll be solving the Axis of Symmetry with Calculus instead.

$f'(x)=2(4x^{2-1})+1(4x^{1-1})-0\\f'(x)=8x+4$

Then let f'(x) = 0 to find the Axis of Symmetry.

$8x+4=0\\8x=-4\\x=-\frac{4}{8}\\x=-\frac{1}{2}$

Therefore, the Axis of Symmetry is -1/2

4. Determine the vertex.

Substitute the value of Axis of Symmetry in f(x).

$f(x)=4(-\frac{1}{2})^2+4(-\frac{1}{2})-3\\f(x)=4(\frac{1}{4})-2-3\\f(x)=1-2-3\\f(x)=-4$

Therefore the vertex is at (-1/2, -4)

5. Does the vertex representing max-pont or min-point?

The vertex represents the minimum point. The graph is upward, meaning the minimum point is the point that gives the LOWEST Y-VALUE.

7. Graph f(x)

Unfortunately I won't be able to graph. But I can tell you to graph a parabola that has the most curve at the vertex and intercepts y-axis at (0,-3).

--------------------------- End of Part 1 --------------------------------

2. Write the general form of Quadratic Function in standard form.

$y=ax^2+bx+c$

The graph can be easily determined about the y-intercept and being an upward or downward parabola along with how narrow or wide the parabola is.

For example, c value is the y-intercept as defined. When a > 0, the parabola is upward and when a < 0, the parabola is downward. The more value of | a | is, the more narrow it will be and the less value of | a | it is, the wider it will be.

3. Write in Factored Form

$y=(x+a)(x+b)\\y=(x-a)(x-b)\\y=(x+a)(x-b)\\y=(x-a)(x+b)$

These are factored forms with different types of operators.

The equation can be easily determined about the roots of equation. For example, if the function is in f(x) = (x+2)(x-1) Then the roots would be x = -2 and 1 as the graph will intercept x-axis at (-2,0) and (1,0)

4. Write in Vertex Form.

$y=a(x-h)^2+k$