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Tomtit [17]
3 years ago
14

X^2+ 6x - 4 = 3x + 6

Mathematics
2 answers:
jolli1 [7]3 years ago
4 0

Answer:

x=2

x=-5

Step-by-step explanation:

You need to get everything on one side to have a quadratic equation:

x^2+6x-4 -(3x+6) = x^2+3x-10

All factors of 10 are 1*10 and 2*5.

5-2 = 3 and 5*-2 = -10

Factoring x^2+3x-10 gives us (x-2)(x+5)

x=2

x=-5

Tanzania [10]3 years ago
4 0

Answer:

x=-5      x=2

Step-by-step explanation:

x^2+ 6x - 4 = 3x + 6

Subtract 3x from each side

x^2+ 6x-3x - 4 = 3x-3x + 6

x^2+ 3x - 4 =  6

Subtract 6 from each side

x^2+ 3x - 4-6 = 6 - 6

x^2 +3x -10 =0

Factor

What 2 numbers multiply to -10 and add to 3

5*-2 =-10

5+-2 = 3

(x+5) (x-2) =0

Using the zero product property

x+5 =0   x-2 =0

x=-5      x=2

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Gaby plays on volleyball team. In the two games she scored 3/5 of the total number of points her team scored. Her team scored 25
hjlf

Answer:

Gaby scored 27 points.

Step-by-step explanation:

First, you have to find 3/5 of both of the numbers.

What I did was I found 1/5 of each number and multiplied it by 3.

25/5=5, so 1/5 of 25 is 5. 5(3)= 15, so Gaby scored 15 points in the first game.

20/5= 4, so 1/5 of 20 is 4. 4(3)= 12, so Gaby scored 12 points in the second game.

Finally, add 15+12, which equals 27 :).

5 0
3 years ago
Is (3,4) a solution to the system of<br> equations. <br> X + y = 7<br> x - 2y = - 5
Anuta_ua [19.1K]

Answer: Yes, the point (3,4) is a solution to the system.

===================================================

Proof of this:

Replace x with 3 and y with 4 in the first equation

x+y = 7

3+4 = 7

7 = 7

This confirms the first equation. Repeat for the second equation

x-2y = -5

3-2(4) = -5

3 - 8 = -5

-5 = -5

We get true equations for both when we plug in (x,y) = (3,4). This confirms it is a valid solution to the system of equations. It turns out it's the only solution to this system of equations. Visually, the two lines cross at the single location (3,4).

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Answer:

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Step-by-step explanation:

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