X = cost of children's ticket
x +3 = cost of adults tickets
100x + 200(x+3) = 2100
100x + 200x + 600 = 2100
300x = 1500
x = 5
answer
children ticket costs $5
Answer:
it is array model
i hope this answer will help you
I'll walk you through the first one, and then you should be able to do the rest.
The first step is to right out your numbers from least to greatest
Problem #1: 2,4,5,6,8,10,13,17,19,20
To find the MEDIAN, you're simply crossing out a number from each end until you meet in the middle. In this case, you have an even number of data, which means once you get to the middle, you're have to find the average.
In this problem, your two middle numbers are 8 & 10. Since only one number can be the median, you add them together, and divide by 2:
8+10=18 18/2=9 < this is your middle, or MEDIAN
Next, your first and third quartiles-- they're the median of the lower half and data, and upper half.
For the lower quartile, find the mean of 2,4,5,6, and 8. again, cross out one from each side until you get to the middle. FIRST QUARTILE = 5
Do the same process for the upper half of data (10,13,17,19 & 20).
THIRD QUARTILE = 17
The MIN is the lowest number of data = 2
The MAX is the highest number of data = 20
Best of luck!
Assume that a study of 500 randomly selected airplane routes showed that 482 arrived on time. Select the correct interpretation of the probability of an airplane arriving late. Interpret an event as significant if its probability is less than or equal to 0.05.
Answer: We are given that out of 500 randomly selected airplanes, 482 arrived on time.
Therefore, the probability of airplane being on time 
And the probability of airplane being late 
Since the probability of airplane being late is 0.036, which is less than 0.05, therefore the event is significant at 0.036
