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Natasha2012 [34]
3 years ago
5

Explain how you can compare the cost of two items that are different sizes.

Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer: First find the unit price for each. Then compare the unit prices. The item that has the lesser unit cost is the better buy.  

This was the example answer for this question, just add and move around the words to get a great unique answer. Hope this helps you!

Maru [420]3 years ago
4 0

Answer:

Compare the cost for the each (smallest) unit.

Step-by-step explanation:

You can calculate the cost per unit

For example :

20 ounces of water of brand A cost 1.50

30 ounces of water of brand A cost 2

20 ounces of water cost 1.50/20 = 0.075 dollar per ounce

30 ounces of water cost 2/30 = 0.0677 dollar per ounce

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tigry1 [53]

Answer:

True

Step-by-step explanation:

6x² - 4y - 3x + 6x² + 8x = 12x² + 5x - 4y

Regroup terms on left

6x² + 6x² - 3x + 8x - 4y = 12x² + 5x - 4y

Combine like terms

on left

12x² + 5x - 4y = 12x² + 5x - 4y     True

7 0
3 years ago
The step work of the question along with the answer​
Travka [436]

Answer: RM 31631

Step-by-step explanation:

We are given the following formula, used to calculate the value of an used car according to the years after the car was originally bought:

RM 57000(\frac{8}{9})^{n}

Where RM 57000 is the price of the car when it was bought new, and n=5 is the number of years the car was used.

Solving the formula with the given data:

RM 57000(\frac{8}{9})^{5}=RM 31630.95 This is the value of the car according to the formula.

However, this value can be approximated to:

RM 31631

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3 years ago
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for the first one it is the second option because of one property of logarithms:

log(a)-log(b)=log\frac{a}{b}

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