Answer:
Question 9: Variables: (smallest) s, q, r (largest)
Question 10: 5 whole numbers (7, 8, 9, 10, and 11)
Step-by-step explanation:
For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>
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For question 10, it states
. This can be split into
and
. When x is 12 in the first equation then
and when x is 6 in the second equation
(0.5 is also
). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.
Answer:
y - 0 = -3/4(x - 8)
y = -3/4x + 6
Step-by-step explanation:
Midpoint Formula: (

,

)
Midpoint = (

,

)
Midpoint = (

,

)
Midpoint = (

, -4)
So, the midpoint of the endpoints (-4,-3) and (7,-5) is (

, -4).
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Observation one
From the markings on the diagram <1 = 60o The left triangle is at least isosceles. Therefore equal sides produce equal angles opposite them.
Now we have accounted for 2 angles that are equal (each is 60 degrees) and add up to 120 degrees. The third angle (angle 2) is found from this equation.
<1 + 60 + <2 = 180 degrees. All triangles have 180 degrees.
60 + 60 + <2 = 180
Observation 2
<2 = 60 degrees.
120 + <2 = 180
m<2 = 180 - 120
m<2 = 60 degrees.
Observation 3
m<3 = 120
<2 and <3 are supplementary.
Any 2 angles on the same straight line are supplementary
60 + <3 = 180
<3 = 180 - 60
<3 = 120
Observation 4
m<4 = 40 degrees.
All triangles have 180 degrees. No exceptions.
m<4 + 20 +m<3 = 180
m<4 + 20 + 120 = 180
m<4 + 140 = 180
m<4 = 180 - 140
m<4 = 40
Answer:
1/3 AMOSC T.rhecc
Step-by-step explanation: