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ohaa [14]
3 years ago
13

James has a bicycle. Each wheel has diameter 45cm. James cycles his bicycle in a straight line in the playground. The front whee

l makes 15 complete revolutions. How far does the bicycle travel? Give your answer in metres.
Mathematics
1 answer:
Korvikt [17]3 years ago
5 0

Answer: 21.21 meters

Step-by-step explanation:

Hi, to answer this, first we have to calculate the circumference (C) of the wheel:

C = π x diameter

Replacing with the values given:

C = π x 45 = 141.37 cm

Then we multiply it by the number of revolutions:

141.37 x 15 = 2,120.6 cm

Since  

1 cm = 0.01 m

2,120.6 x 0.01 = 21.21 meters

Feel free to ask for more if needed or if you did not understand something.

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An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Determine whether the relation represents a function.
-Dominant- [34]

Answer:

it does not because it would not pass the straight line test

Step-by-step explanation:

sorry if its wrong and btw your cute

6 0
2 years ago
26•26^8 i’m not sure how to solve this
alexira [117]

Answer:

26^9

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
jenyasd209 [6]
(x+6)^2 +(y+10)^2 = 20

5 0
3 years ago
Read 2 more answers
The variance of any standard normal distribution is________.<br> a) 0.5.b) -0.5.c) 0.d) 1.
goblinko [34]

Answer:

d) 1

Step-by-step explanation:

The variance of standard normal distribution is simply put as 1.

If you take it a bit further, even though not asked, the mean of a standard normal distribution is 0.

Therefore, the conclusion is that, the variance of a standard normal distribution is 1, while the mean of the same standard normal distribution is 0

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3 years ago
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