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Delvig [45]
2 years ago
5

Pls help me figure this out !!

Mathematics
1 answer:
scZoUnD [109]2 years ago
4 0

Answer:

I don't really see two or three points that are coplanar, so My guess would have to be either point G, E, or F.

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Peter played his favorite video game for 10 hours last week. Today Peter's parents restricted him to 5 hours a week for the next
Alexeev081 [22]
 we are given in the problem the number of hours Peter has played for video games. In this case, f(x) is the number of hours of playing with x as the number of weeks of playing. In this case, the equation f(x) = 5x. 
3 0
2 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
2 years ago
What is the value of x?
katovenus [111]

Answer:

it's not even in the pic

Step-by-step explanation:

the q isn't even there

3 0
3 years ago
30 POINTS!!
Anuta_ua [19.1K]
Answer is D


Step by step explanation
7 0
3 years ago
Sara sells dishwashers. She earns an 8% commission on sales. How much must he sell in order to earn $3000?
andrezito [222]
Well, if we look at a calculator and ask, what is 8% of 3000$ we get the answer of 240 dollars.

3000 - 8% = 2760 therefor we know it removes 240 dollars. So the commission is 240 dollars.
8 0
3 years ago
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