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Ira Lisetskai [31]
2 years ago
9

Which two charges have a sum of 0? (1 point) a +6 charge and +6 charge b −6 charge and −6 charge c +6 charge and 0 charge d +6 c

harge and −6 charge
Mathematics
1 answer:
Roman55 [17]2 years ago
6 0

Answer:

+6 charge and −6 charge

Step-by-step explanation:

In this problem, we need to find two charges that have a sum of 0.

In option (d), both charges have the same magnitude. But they have opposite charges.

Sum means to add up charges i.e.

+6 charge +(-6) charge = 0 (they have opposite charges)

Hence, the correct option is (d).

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On a scale drawing of a rectangular closet, the length is 125 inches and the width is 3 inches.
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Scale Factor 1: 42

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Find actual length for 125 inches:
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125 x 42 = 5250 inches

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Find actual length for 3 inches:
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3 x 42 = 126 inches

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Dimension of the actual closet:
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5250 inches by 126 inches
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Is math important in real life?
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Brenda throws a dart at this square-shaped target:
Klio2033 [76]

Answer: See below

Step-by-step explanation:

<u>Area of the square</u>  = l*w = 11*11 = 121  

<u>Area of the circle</u>  = pi r^2 = pi*1^2 =  3.142

<u>Part A</u>

P(hitting the circle) = 3.142 / 121  =  0.026 which is closer to 0.

<u>Part B</u>

P(hitting the outside portion)  = 1 - 0.026 = 0.974 which is closer to 1.  

4 0
2 years ago
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X2 - x - 42 <br>a=? <br>b=? <br>C=? <br><br><br><br>help me ​
lisabon 2012 [21]

Step-by-step explanation:

thr standard form for a quadratic equation is:

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6 0
2 years ago
Solve the system by substitution.
kirill [66]
<h2>Answer:</h2>

x = 1

y = 1

<h3>Step-by-step explanation:</h3>

y=-3x+4\\ y=x

Substitute into one of the equations

-3x+4=x

Rearrange variables to the left sider of the equation

-3x-x=-4

Combine like terms

-4x=-4

Divide both sides of the equation by the coefficient of variable

x=\frac{-4}{-4}

Determine the sign for multiplication or division

x=\frac{4}{4}

Cross out the common factor

x=1

Substitute into one of the equations

y=1

The solution of the system is

\left \{ {{x=1} \atop {y=1}} \right.

<em>I hope this helps you</em>

<em>:)</em>

8 0
2 years ago
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