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tatyana61 [14]
3 years ago
5

Hannah and Anthony are sibling who have ages that are consecutive odd integers. The sum of their ages is 92. Which equations cou

ld be used to find Hannah’s age, h, is she is the older sibling? Select all that apply:
a) 2h + 1 = 92
b) 2h – 1 = 92
c) 2h + 2 = 92
d) 2h – 2 = 92
e) h – 2 = 92 – h
f) h – 1 = 92 – h
Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0
E h-2 =92 -h that is the correct answer
Yuki888 [10]3 years ago
4 0

Answer:You have to ask your teacher

Step-by-step explanation: i couldnt do it but she gave it to us because she said that its to hard

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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

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\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

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3 years ago
Please I need answers​
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9, 11, 1, 0, 11

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