Answer:
Step-by-step explanation:
Like terms have same variable with same power. Combine like terms
153y³ + 132y² + 6y - 5 - 3y³ - 5y² +4y - 2
= <u>153y³ - 3y³</u> + 132y² - 5y² + 6y + 4y <u> -5 - 2</u>
= <u>150y³</u> + 127y² + 10y<u> - 7</u>
Answers: b, d and e
b.The graph has a relative minimum
d. The graph has an x intercept at 3,0
e. the graph has an y intercept at 0,-15
f(x)=(x+5)(x-3)
The given equation is in the form of f(x) = a(x-b)(x-c)
If 'a' is positive then graph has a relative minimum
If 'a' is negative then graph has a relative maximum
Here a=1 that is positive so graph has a relative minimum .
To find x intercept we set f(x) =0 and solve for x
0=(x+5)(x-3)
x+5 =0 -> x = -5 so x intercept is (-5,0)
x - 3=0 -> x= 3 so x intercept is (3,0)
To find y intercept we plug in 0 for x
y=(x+5)(x-3)
y=(0+5)(0-3) = -15
so y intercept is (0,-15)
Answer:
r= 9
Step-by-step explanation:
radius (r) = diameter (D)/2
= 18/2
= 9
u - v = <5, 2> - <2, - 3> = <5 - 2, 2 + 3> = <3, 5>
given a vector <u, v> then the magnitude is √ (u² + v² ) and it's angle of direction is
θ = 
(
)
thus the magnitude of <3, 5> = √(3² + 5²) = √34 ≈ 5.83 ( to 2 dec. places )
Θ = (
) = 59.04° ( to 2 dec. places )
