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3 years ago

M + 20 = 11m - 6 can somebody show me how to solve this?

1 answer:

7 0

This ends up being:

-10m = -26

M= 2.6

Basically you’re doing basic algebra. You take the “11m” and subtract it to the positive (1) m. And you basically should see 1m-11m EQUALING -10m. Don’t let the negatives confuse you.

Then you take the 20 and subtract it to -6. It should look like: -6-20 = -26.

Then divide-10 to -26, then you should get 2.6. And yes positive!!

Hope this helped!

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A mountain climber is standing at the top of Mount Everest. The distance from the summit to the horizon is 210 miles. About how

igor_vitrenko [27]

Let DE, the height of mount Everest be x.

The center of the earth (point C), the horizont vanishing point (point H) and the top of mount Everest (point E) form a right triangle, where:

the hypothenuse is |EC|=|ED|+|DC|=x+4000 (DC is a radius)
|HC|=4000 mi
|HE|=210 mi

by the Pythagorean theorem:

$(x+4000)^{2}= 4000^{2} + 210^{2}$

$(x+4000)^{2}=16000000+44100=16044100$

taking the square roots of both sides we get:

$x+4000=+- \sqrt{16044100} =+-4005.5087$

so x=-4000+4005.5087 miles = 5.5087 miles
or x= -4000-4005.5 which is negative so not a solution to our problem

Answer: 5.5087 miles

7 0

4 years ago

What is (-6)^8/(-6)^2

siniylev [52]

-6^8/(-6)^2
1679616/6^2
1679616/36
=46656

3 0

3 years ago

Read 2 more answers

Consider the simple linear regression model Yi=β0+β1xi+ϵi, where ϵi's are independent N(0,σ2) random variables. Therefore, Yi is

Virty [35]

Answer:

See proof below.

Step-by-step explanation:

If we assume the following linear model:

$y = \beta_o + \beta_1 X +\epsilon$

And if we have n sets of paired observations $(x_i, y_i) , i =1,2,...,n$ the model can be written like this:

$y_i = \beta_o +\beta_1 x_i + \epsilon_i , i =1,2,...,n$

And using the least squares procedure gives to us the following least squares estimates $b_o$ for $\beta_o$ and $b_1$ for $\beta_1$ :

$b_o = \bar y - b_1 \bar x$

$b_1 = \frac{s_{xy}}{s_xx}$

Where:

$s_{xy} =\sum_{i=1}^n (x_i -\bar x) (y-\bar y)$

$s_{xx} =\sum_{i=1}^n (x_i -\bar x)^2$

Then $\beta_1$ is a random variable and the estimated value is $b_1$ . We can express this estimator like this:

$b_1 = \sum_{i=1}^n a_i y_i$

Where $a_i =\frac{(x_i -\bar x)}{s_{xx}}$ and if we see careful we notice that $\sum_{i=1}^n a_i =0$ and $\sum_{i=1}^n a_i x_i =1$

So then when we find the expected value we got:

$E(b_1) = \sum_{i=1}^n a_i E(y_i)$

$E(b_1) = \sum_{i=1}^n a_i (\beta_o +\beta_1 x_i)$

$E(b_1) = \sum_{i=1}^n a_i \beta_o + \beta_1 a_i x_i$

$E(b_1) = \beta_1 \sum_{i=1}^n a_i x_i = \beta_1$

And as we can see $b_1$ is an unbiased estimator for $\beta_1$

In order to find the variance for the estimator $b_1$ we have this:

$Var(b_1) = \sum_{i=1}^n a_i^2 Var(y_i) +\sum_i \sum_{j \neq i} a_i a_j Cov (y_i, y_j)$

And we can assume that $Cov(y_i,y_j) =0$ since the observations are assumed independent, then we have this:

$Var (b_1) =\sigma^2 \frac{\sum_{i=1}^n (x_i -\bar x)^2}{s^2_{xx}}$

And if we simplify we got:

$Var(b_1) = \frac{\sigma^2 s_{xx}}{s^2_{xx}} = \frac{\sigma^2}{s_{xx}}$

And with this we complete the proof required.

8 0

4 years ago

A jeweler is selling bracelets at an art convention. it costs $135 to obtain a booth at the convention. the cost to make a singl

tangare [24]

Answer:

(a) Loss from selling 15 necklaces

(b) $b > 18$

Step-by-step explanation:

The question has missing details. (See the comment section for missing details)

Given

$12b > 135 + 4.50b$

Solving (a): Will she make a profit from 15 necklaces

To do this, we substitute 15 for b in $12b > 135 + 4.50b$

$12 * 15 > 135 + 4.50 * 15$

$180 > 202.5$

The inequality is not true.

Hence, she'll make a loss from selling 15 necklaces

Solving (b): An expression that represents profit.

To do this, we solve for b in $12b > 135 + 4.50b$

Collect Like Terms

$12b - 4.50b > 135$

$7.5b > 135$

Make b the subject

$b > \frac{135}{7.5}$

$b > 18$

This implies that to make a profit, she must sell more than 18 necklaces.

6 0

3 years ago

Find the slope 3x+5y=29

tester [92]

Answer: $-\frac{3}{5}$

Step-by-step explanation:

If you solve for y, then it will be in y = mx + b format where m is the slope.

3x + 5y = 29

-3x -3x

5y = -3x + 29

$\frac{5y}{5} = \frac{-3x}{5} + \frac{29}{5}$

$y = \frac{-3}{5}x + \frac{29}{5}$

m = $-\frac{3}{5}$

3 0

3 years ago