Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
Answer
Step-by-step explanation: example
5/(X+2). + 2/(X+1)
Common denominator. Is both (X+2)(X+1)
So the first fraction needs (X+1) since it already has (X+2) the second fraction needs ( X+2)
5(X+1). / (X+2)((X+1) +. 2/(X+2)/(X+1)
So multiply 5 with X then 5 with 1 and 2 times X and 2 times 2
5x+5 + 2x+4 / (X+2)((X+1)
Answer 7x+9/ (X+2)(X+1)
Answer:
The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.
Step-by-step explanation:
The volume of the sphere (
), measured in cubic feet, is represented by the following formula:

Where
is the radius of the sphere, measured in feet.
The change in volume is obtained by means of definition of total difference:

The derivative of the volume as a function of radius is:

Then, the change in volume is expanded:

If
and
, the change in the volume of the sphere is approximately:


The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.
Answer:
218
Step-by-step explanation:
14 x 12 = 168 + 50 = 218
idf.k why u sent that pic, also your welcome.
Answer:
-343/27
Step-by-step explanation: