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Law Incorporation [45]
3 years ago
8

Solve 2x - 1 < 3 a) x>1 b) x>2 c) x<2 d) x<1 e) x<-2

Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

c) x<2

Step-by-step explanation:

2x-1<3

add 1 to both side gets 2x<4

divide 2 to both sides gets x<2

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Alise separated her pictures into 3 piles. Each pile contained 9 pictures. How many pictures did she have in all? Write and and
expeople1 [14]
3 piles of 9 pictures is 27. Because 9*3=27. So, your answer should say "Alise had 27 pictures in all because 9*3=27"
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Shirt cost $20 each and ties cost $12 each. Write an expression for the cost of s shirts and t ties
Ierofanga [76]
20s+12t= is your expression.
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elliot is moving a table through a doorway. The table is 2 5/8 ft wide and the doorway is 2 3/4 ft wide.​
MatroZZZ [7]

Answer:

Elliot is able to move the table through, since 2 3/4 is more than 2 5/8.

Step-by-step explanation:

2 3/4 - 2 5/8 = 0.125

0.125 is a positive number.

So, Elliot is able to move the table through the doorway.

<h2><u><em>Please mark as Brainliest!!!</em></u></h2>
7 0
3 years ago
Soup A has 5 grams of sodium in every 12 cups. Soup B has 8 grams of sodium in every 13 cups. Which soup has more sodium per cup
gregori [183]

Answer:

Step-by-step explanation:

5

7 0
3 years ago
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What is the area of trapezoid ABCD ? Enter your answer as a decimal or whole number in the box. Do not round at any steps. units
lidiya [134]

Answer:

37.5 sq. units.

Step-by-step explanation:

The coordinate of vertices of trapezoid ABCD are given,

From the diagram it is clear the area of ABCD = \frac{1}{2}\times AB \times (AD + BC) {Since, AD ║ BC and AB is the perpendicular distance between the parallel lines }

Now, AB = \sqrt{(- 3 - 1)^{2}+ (2 - 5)^{2}  } = 5 units

AD = \sqrt{(- 3 - 0)^{2}+ (2 - (-2))^{2}  } = 5 units

Again, BC = \sqrt{(1-7)^{2}+ (5 - (-3))^{2}  } = 10 units

Therefore, the area of trapezoid ABCD = \frac{1}{2} (10 + 5) \times 5 = 37.5 sq. units. (Answer)

We know, that the distance formula between two points (x_{1}, y_{1}) and  (x_{2}, y_{2}) is  

\sqrt{(x_{1} - y_{1} )^{2} + (x_{2} - y_{2} )^{2}  }.

7 0
3 years ago
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