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ANEK [815]
3 years ago
12

Gideon wants to buy a new video game from the store. They are having a sale on all games, and sell the game at a 15% discount. H

e also has a club card with the store, and gets additional 5% off the sale price. If the original price of the game is $28.00, what is the final sale price that Gideon will pay?
Mathematics
1 answer:
marta [7]3 years ago
4 0

Answer:

5%+15%=20%

to find 20% of 28 u multiply 28 x 0.2= 5.6

so to remove the 20% since it's 20% off u subtract 5.6 from 28

28-5.6= 22.4

Step-by-step explanation:

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3 years ago
PLEASE HELP ASAP!!!!
Veseljchak [2.6K]

Answer:

Step-by-step explanation:

R(0,0)

A=((0+2a)/2,(0+2b)/2)=(a,b)

S(2a,2b)

B=((2a+2c)/2,(2b+2d)/2)=(a+c,b+d)

T(2c,2d)

C=((2c+2c)/2,(2d+0)/2)=(2c,d)

V(2c,0)

D=((2c+0)/2,(0+0)/2)=(c,0)

R(0,0)

slope of AB=(b+d-b)/(a+c-a)=d/c

slope of DC=(d-0)/(2c-c)=d/c

slope of AD=(0-b)/(c-a)=-b/(c-a)

slope of BC=(d-b-d)/(2c-a-c)=-b/(c-a)

7 0
3 years ago
A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
3 years ago
When x-y=3 work out the value of y-x
GalinKa [24]

The value of y-x is (-3)

<u>Solution:</u>

Given: The value of x-y=3

To find: The value of y-x

\bold{x-y=3\rightarrow (1)}

Let's multiply the equation (1) by (- 1) on both sides,

\Rightarrow\bold{(x - y)\times(- 1) = 3\times(- 1)}

\Rightarrow\bold{-(x-y)=-3}

On multiplying the sign,

\Rightarrow\bold{(-x+y)=-3}

The above equation can also be written as,

\Rightarrow\bold{y-x=-3\rightarrow \text{(The required equation)}}

<u>Multiplication of signs:</u>

\Rightarrow( + )\times( + ) = ( + )

\Rightarrow( + )\times( - ) = ( - )

\Rightarrow( - )\times( + ) = ( - )

\Rightarrow( - )\times( - ) = ( + )

In simpler terms, when we multiply two integers with the same signs, the result is always positive and when we multiply two integers with different signs, the result is always negative.

5 0
3 years ago
Is a half bigger then a third ?
Assoli18 [71]


1/2 plus 1/3 is 5/6.

You have to find the common denominator

7 0
3 years ago
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