Consider the following pair of equations:
1 answer:
Answer:
The lines representing these equations intercept at the point (-4,2) on the plane.
Step-by-step explanation:
When we want to find were both lines intercept, we are trying to find a pair of values (x,y) that belongs to both equations, which means that it satisfies both equations at the same time.
Therefore, we can use the second equation that gives us the value of y in terms of x, to substitute for y in the first equation. Then we end up with an equation with a unique unknown, for which we can solve:
Next we use this value we obtained for x (-4) in the same equation we use for substitution in order to find which y value corresponds to this:
Then we have the pair (x,y) that satisfies both equations (-4,2), which is therefore the point on the plane where both lines intercept.
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Answer:
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Step-by-step explanation:
The tangent function has been shifted upward by 2 units, but there has been no horizontal scaling. Any horizontal offset must be equal to some number of whole periods.
Choices A and B show tan( )+2, the correct vertical offset. However, choice A has a horizontal scale factor of 2. The correct choice is B, which has no horizontal scaling (the coefficient of x is 1) and a horizontal offset of π, one full period.
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<em>Comment on horizontal scaling</em>
Horizontal scaling is different from vertical scaling in that using k·x in place of x <em>compresses</em> the graph horizontally by a factor of k. On the other hand, using k·f(x) in place of f(x) <em>expands</em> the graph vertically by a factor of k.
