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Dmitrij [34]
2 years ago
13

What extra number must be included with the following list of numbers to increase the median by 1?

Mathematics
1 answer:
Anna35 [415]2 years ago
7 0
The correct answer is C)18
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If I have 60 coins consisting of dimes and quarters, and if I have x dimes, how many quarters do i have?
Contact [7]
I don't know if I'm correct, I'm guessing... 30
4 0
3 years ago
Read 2 more answers
What is the simple interest earned on $7550 at a 3.9% interest rate for 6 years? Round your answer to the nearest cent.
Maslowich
I'm going to assume the rate, 3.9%, is for one year.

7550 * 3.9 * 6 = $176, 670 is the simple interest earned in 6 years with a rate of 3.9% per year.


Since you have the formula, why don't you do it yourself?
4 0
3 years ago
Task 1 Nonlinear Systems of Equations Create a system of equations that includes one linear equation and one quadratic equation.
Luden [163]

Answer:

hope this helps

Step-by-step explanation:

solution:

x^2 + 3x + 5 = x + 13

x^2 + 2x -8 = 0

(x+4)(x-2) = 0

x = -4 or x = 2

if x = -4, y = 9

if x = 2 , y = 15

4 0
3 years ago
1) Diego measured the number of cups of water in 15 bottles of various sizes. He
Ivan

Answer:

8\frac{3}{4} cups.

Step-by-step explanation:

From the line plot made by Diego which represents bottle sizes in cups, we can see that the most common size is the bottle having 1¾ cups (there are 5 of this sizes).

If he poured all 5 of this bottle sizes in 1 container, he would have the following:

1\frac{3}{4} * 5 = \frac{7}{4}*5 = \frac{35}{4}

= 8\frac{3}{4} cups.

6 0
3 years ago
You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and
Llana [10]

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted R^2 :

Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}

Where k= number of regressors in the model.

Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205

3 0
3 years ago
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